Merge branch 'master' of github.com:failedxyz/easyctf

fizz-buzz-1/description.md

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+Write a program that outputs the numbers 1 through n, in incremental order, one per line. 
+
+However, replace any line that is a multiple of 3 with "Fizz" and any that are a multiple of 5 with "Buzz". Any line that is a multiple of 3 and 5 should be written as "FizzBuzz".
+
+The input will be the number of lines to write, n, followed by a linebreak.
+
+Sample output:
+
+```
+1
+2
+Fizz
+4
+Buzz
+
+...
+
+13
+14
+FizzBuzz
+16
+17
+
+...
+```

fizz-buzz-1/grader.py

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+def grade(random, key):
+    if key.find("PUT A NEW KEY HERE!!!!") != -1:
+        return True, "Correct!"
+    return False, "Nope."

fizz-buzz-1/problem.yml

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+title: Fizz Buzz 1
+category: Programming
+value: 10
+author: wiresboy
+autogen: false

fizz-buzz-1/todo.txt

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+I still need to do the graders.

fizz-buzz-2/description.md

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+Oh no! Two of my keys are broken! Please help me make the same Fzz Buzz program, sans that one letter and queston marks.

fizz-buzz-2/grader.py

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+def grade(random, key):
+    if key.find("PUT A NEW KEY HERE!!!!") != -1:
+        return True, "Correct!"
+    return False, "Nope."

fizz-buzz-2/problem.yml

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+title: Fzz Buzz 2
+category: Programming
+value: 200
+hint: Have fun!
+author: wresboy
+autogen: false

fizz-buzz-2/todo.txt

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+I still need to do the execution grader, and probably introduce some sort of limits to prevent the contestant from having a print "1,2,fizz,4,buzz..." type program. A length limit would probably be sufficient.
+
+I also need to add a program validator, that checks for the characters "i", "I", and "?".
+
+We will need to disable "eval()", "exec()", globals (in python), etc.
+
+Backup hint: `Don't use the characters "i", "I", and "?".`

flag-peg/description.md

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+We found a flag but it didn't do anything. Maybe you can find a better [flag](${heresaflag_jpg})?

flag-peg/grader.py

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+def grade(autogen, key):
+    if key.find("1_wr073_7h15_1n_m5p41n7") != -1:
+        return True, "Correct!"
+    return False, "Nope!"

flag-peg/problem.yml

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+author: GenericNickname
+title: Flag PEG
+hint: You're not looking deep enough
+category: Forensics
+autogen: false
+programming: false
+value: 50
+files:
+  - heresaflag.jpg

match-me/description.md

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+When making pairings between two sets of objects based on their preferences (in this case people), there can be multiple stable solutions, stable meaning that no two elements would prefer to be matched with each other over their current matching.
+A side-effect of having multiple solutions is that there are solutions favor one group over the other.
+
+We received two files, one listing men and the other women. Each line contains a name, followed by a series of numbers. Each number N corresponds to their preference to be matched with the Nth member of the opposite list, with 1 being the highest.
+
+For example, the entry "Joe 4, 5, 3, 1, 2" means that Joe would most prefer the 4th entry on the opposite list, and least prefer the 2nd.
+
+We have heard that there is one pairing which will be together in all possible stable matchings, please discover who this couple is and provide their names as "<male_name>,<female_name>"
+
+Here are the lists of preferences:[male preferences](${male_prefs_txt}), [female preferences](${female_prefs_txt}).

match-me/grader.py

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+def grade(autogen, key):
+    if key.find("Paris,Blair") != -1:
+        return True, "Correct!"
+    return False, "Nope!"

match-me/problem.yml

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+author: GenericNickname
+title: Match Me
+hint: This is a fairly well-known graph problem, there's probably some sort of internet source on it.
+category: Algorithms
+autogen: false
+programming: false
+value: 50
+files:
+  - female_prefs.txt
+  - male_prefs.txt