From b33d60190080e6b73b568ae479242c7f1a1eee88 Mon Sep 17 00:00:00 2001 From: Michael Zhang Date: Fri, 20 Sep 2024 13:18:22 -0500 Subject: [PATCH] update to use mathsf --- .../2024-06-28-boolean-equivalences.lagda.md | 32 +++++++++---------- src/pages/posts/[...slug].astro | 2 +- 2 files changed, 17 insertions(+), 17 deletions(-) diff --git a/src/content/posts/2024-06-28-boolean-equivalences.lagda.md b/src/content/posts/2024-06-28-boolean-equivalences.lagda.md index e7d578c..af0f829 100644 --- a/src/content/posts/2024-06-28-boolean-equivalences.lagda.md +++ b/src/content/posts/2024-06-28-boolean-equivalences.lagda.md @@ -32,7 +32,7 @@ open Ξ£ With just that notation, the problem may not be clear. $2$ represents the set with only two elements in it, which is the booleans. The -elements of $2$ are $\textrm{true}$ and $\textrm{false}$. +elements of $2$ are $\mathsf{true}$ and $\mathsf{false}$. ``` data 𝟚 : Set where @@ -53,8 +53,8 @@ shown by Theorem 4.1.3 in the [HoTT book][book]. [1]: https://en.wikipedia.org/wiki/Homotopy#Homotopy_equivalence - there exists a $g : B \rightarrow A$ -- $f \circ g$ is homotopic to the identity map $\textrm{id}_B : B \rightarrow B$ -- $g \circ f$ is homotopic to the identity map $\textrm{id}_A : A \rightarrow A$ +- $f \circ g$ is homotopic to the identity map $\mathsf{id}_B : B \rightarrow B$ +- $g \circ f$ is homotopic to the identity map $\mathsf{id}_A : A \rightarrow A$ We can write this in Agda like this: @@ -92,7 +92,7 @@ function along with proof of its equivalence properties using a dependent pair[^dependent-pair]: [^dependent-pair]: A dependent pair (or $\Sigma$-type) is like a regular pair $\langle x, y\rangle$, but where $y$ can depend on $x$. - For example, $\langle x , \textrm{isPrime}(x) \rangle$. + For example, $\langle x , \mathsf{isPrime}(x) \rangle$. In this case it's useful since we can carry the equivalence information along with the function itself. This type is rather core to Martin-LΓΆf Type Theory, you can read more about it [here][dependent-pair]. @@ -184,8 +184,8 @@ Now we need another function in the other direction. We can't case-split on functions, but we can certainly case-split on their output. Specifically, we can differentiate `id` from `neg` by their behavior when being called on `true`: -- $\textrm{id}(\textrm{true}) :\equiv \textrm{true}$ -- $\textrm{neg}(\textrm{true}) :\equiv \textrm{false}$ +- $\mathsf{id}(\mathsf{true}) :\equiv \mathsf{true}$ +- $\mathsf{neg}(\mathsf{true}) :\equiv \mathsf{false}$ ``` g : (𝟚 ≃ 𝟚) β†’ 𝟚 @@ -207,7 +207,7 @@ everything to true, since it can't possibly have an inverse. We'll come back to this later. -First, let's show that $g \circ f \sim \textrm{id}$. This one is easy, we can +First, let's show that $g \circ f \sim \mathsf{id}$. This one is easy, we can just case-split. Each of the cases reduces to something that is definitionally equal, so we can use `refl`. @@ -217,7 +217,7 @@ g∘f true = refl g∘f false = refl ``` -Now comes the complicated case: proving $f \circ g \sim \textrm{id}$. +Now comes the complicated case: proving $f \circ g \sim \mathsf{id}$. > [!admonition: NOTE] > Since Agda's comment syntax is `--`, the horizontal lines in the code below @@ -235,9 +235,9 @@ module f∘g-case where f∘g eqv = goal eqv ``` -Now our goal is to show that for any equivalence $\textrm{eqv} : 2 \simeq 2$, +Now our goal is to show that for any equivalence $\mathsf{eqv} : 2 \simeq 2$, applying $f ∘ g$ to it is the same as not doing anything. We can evaluate the -$g(\textrm{eqv})$ a little bit to give us a more detailed goal: +$g(\mathsf{eqv})$ a little bit to give us a more detailed goal: ``` goal2 : @@ -273,27 +273,27 @@ a syntax known as [with-abstraction]: We can now case-split on $b$, which is the output of calling $f$ on the equivalence returned by $g$. This means that for the `true` case, we need to -show that $f(b) = \textrm{bool-eqv}$ (which is based on `id`) is equivalent to +show that $f(b) = \mathsf{booleqv}$ (which is based on `id`) is equivalent to the equivalence that generated the `true`. Let's start with the `id` case; we just need to show that for every equivalence $e$ where running the equivalence function on `true` also returned `true`, $e -\equiv f(\textrm{true})$. +\equiv f(\mathsf{true})$. Unfortunately, we don't know if this is true unless our equivalences are _mere propositions_, meaning if two functions are identical, then so are their equivalences. $$ - \textrm{isProp}(P) :\equiv \prod_{x, y: P}(x \equiv y) + \mathsf{isProp}(P) :\equiv \prod_{x, y \, : \, P}(x \equiv y) $$ Definition 3.3.1 from the [HoTT book][book] -Applying this to $\textrm{isEquiv}(f)$, we get the property: +Applying this to $\mathsf{isEquiv}(f)$, we get the property: $$ - \sum_{f : A β†’ B} \left( \prod_{e_1, e_2 : \textrm{isEquiv}(f)} e_1 \equiv e_2 \right) + \sum_{f : A β†’ B} \left( \prod_{e_1, e_2 \, : \, \mathsf{isEquiv}(f)} e_1 \equiv e_2 \right) $$ This proof is shown later in the book, so I will use it here directly without proof[^equiv-isProp]: @@ -314,7 +314,7 @@ equivalences must not map both values to a single one. This way, we can pin the behavior of the function on all inputs by just using its behavior on `true`, since its output on `false` must be _different_. -We can use a proof that [$\textrm{true} \not\equiv \textrm{false}$][true-not-false] that I've shown previously. +We can use a proof that [$\mathsf{true} \not\equiv \mathsf{false}$][true-not-false] that I've shown previously. [true-not-false]: https://mzhang.io/posts/proving-true-from-false/ diff --git a/src/pages/posts/[...slug].astro b/src/pages/posts/[...slug].astro index ae9da1d..0706443 100644 --- a/src/pages/posts/[...slug].astro +++ b/src/pages/posts/[...slug].astro @@ -63,7 +63,7 @@ const excerpt = remarkPluginFrontmatter.excerpt?.replaceAll("\n", ""); { post.data.draft && ( - +