naturals exercises
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4 changed files with 62 additions and 23 deletions
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.gitignore
vendored
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.gitignore
vendored
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@ -30,6 +30,7 @@ Gemfile.lock
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## Emacs files
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auto/
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\#*\#
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## Misc build files
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out/
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@ -1,3 +1,11 @@
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(require 'use-package)
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(require 'use-package-ensure)
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(setq use-package-always-ensure t)
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(use-package evil)
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(use-package agda2-mode)
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(use-package gruvbox-theme)
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(setq evil-undo-system 'undo-tree)
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(require 'evil)
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(evil-mode 1)
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30
flake.nix
30
flake.nix
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@ -1,12 +1,16 @@
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{
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inputs.nixpkgs.url = "github:nixos/nixpkgs?rev=860b56be91fb874d48e23a950815969a7b832fbc";
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inputs.flake-utils.url = "github:numtide/flake-utils";
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inputs.plfa.url = "github:plfa/plfa.github.io";
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inputs.plfa.flake = false;
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inputs = {
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nixpkgs.url = "github:nixos/nixpkgs?rev=860b56be91fb874d48e23a950815969a7b832fbc";
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flake-utils.url = "github:numtide/flake-utils";
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plfa = {
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flake = false;
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url = "github:plfa/plfa.github.io";
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};
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};
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outputs = { self, nixpkgs, flake-utils, plfa }:
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flake-utils.lib.eachDefaultSystem
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(system:
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flake-utils.lib.eachDefaultSystem (system:
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let
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pkgs = nixpkgs.legacyPackages.${system};
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agda = pkgs.agda.withPackages (p: [
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@ -32,17 +36,17 @@
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]) ++ (with epkgs.elpaPackages; [
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undo-tree
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]));
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in {
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devShell =
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pkgs.mkShell {
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in
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{
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devShell = pkgs.mkShell {
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buildInputs = [
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emacsWithPackages
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agda
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pkgs.vscodium
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];
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shellHook = ''
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XDG_CONFIG_HOME=$(pwd) emacs
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'';
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};
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});
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}
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);
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}
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@ -81,7 +81,7 @@ successor of two; and so on.
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Write out `7` in longhand.
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```
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-- Your code goes here
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_ = suc (suc (suc (suc (suc (suc (suc zero))))))
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```
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@ -427,7 +427,8 @@ other word for evidence, which we will use interchangeably, is _proof_.
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#### Exercise `+-example` (practice) {name=plus-example}
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Compute `3 + 4`, writing out your reasoning as a chain of equations, using the equations for `+`.
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Compute `3 + 4`, writing out your reasoning as a chain of equations, using the
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equations for `+`.
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```
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-- Your code goes here
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@ -506,7 +507,9 @@ Define exponentiation, which is given by the following equations:
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Check that `3 ^ 4` is `81`.
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```
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-- Your code goes here
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_^_ : ℕ → ℕ → ℕ
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m ^ zero = 1
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m ^ suc n = m * ( m ^ n)
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```
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@ -919,6 +922,29 @@ Confirm that these both give the correct answer for zero through four.
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```
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-- Your code goes here
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inc : Bin → Bin
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inc ⟨⟩ = ⟨⟩ O
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inc (n O) = n I
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inc (⟨⟩ I) = ⟨⟩ I O
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inc (n I) = (inc n) O
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_ : inc (⟨⟩ I O I I) ≡ ⟨⟩ I I O O
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_ = refl
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to : ℕ → Bin
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to zero = ⟨⟩ O
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to (suc n) = inc (to n)
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from : Bin → ℕ
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from ⟨⟩ = 0
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from (n O) = 2 * (from n)
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from (n I) = 2 * (from n) + 1
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_ : to 12 ≡ ⟨⟩ I I O O
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_ = refl
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_ : from (⟨⟩ I O I I) ≡ 11
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_ = refl
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```
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