2013-08-25 01:02:38 +00:00
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/*
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Copyright (c) 2013 Microsoft Corporation. All rights reserved.
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Released under Apache 2.0 license as described in the file LICENSE.
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Author: Leonardo de Moura
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*/
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#pragma once
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2013-08-30 03:12:43 +00:00
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#include <memory>
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#include "environment.h"
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2013-08-31 23:46:41 +00:00
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#include "formatter.h"
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2013-08-25 01:02:38 +00:00
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namespace lean {
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class frontend;
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2013-08-25 01:02:38 +00:00
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/**
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\brief Expression elaborator, it is responsible for "filling" holes
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in terms left by the user. This is the main module resposible for computing
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the value of implicit arguments.
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*/
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class elaborator {
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2013-08-30 03:12:43 +00:00
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class imp;
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std::shared_ptr<imp> m_ptr;
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static void print(imp * ptr);
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public:
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explicit elaborator(frontend const & fe);
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~elaborator();
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expr operator()(expr const & e);
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2013-09-04 01:00:30 +00:00
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expr operator()(expr const & e, expr const & expected_type);
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2013-08-31 23:46:41 +00:00
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/**
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\brief If \c e is an expression instantiated by the elaborator, then it
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returns the expression (the one with "holes") used to generate \c e.
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Otherwise, it just returns \c e.
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*/
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expr const & get_original(expr const & e) const;
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2013-08-30 03:12:43 +00:00
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void set_interrupt(bool flag);
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void interrupt() { set_interrupt(true); }
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void reset_interrupt() { set_interrupt(false); }
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2013-08-25 18:18:19 +00:00
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void clear();
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environment const & get_environment() const;
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void display(std::ostream & out) const;
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2013-08-31 23:46:41 +00:00
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format pp(formatter & f, options const & o) const;
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2013-09-04 20:21:57 +00:00
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bool has_constraints() const;
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};
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2013-09-01 17:24:10 +00:00
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/**
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\brief Create a choice expression for the given functions.
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It is used to mark which functions can be used in a particular application.
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The elaborator decides which one should be used based on the type of the arguments.
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\pre num_fs >= 2
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*/
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expr mk_choice(unsigned num_fs, expr const * fs);
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/**
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\brief Return true iff \c e is an expression created using \c mk_choice.
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*/
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bool is_choice(expr const & e);
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/**
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\brief Return the number of alternatives in a choice expression.
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We have that <tt>get_num_choices(mk_choice(n, fs)) == n</tt>.
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\pre is_choice(e)
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*/
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unsigned get_num_choices(expr const & e);
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/**
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\brief Return the (i+1)-th alternative of a choice expression.
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\pre is_choice(e)
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\pre i < get_num_choices(e)
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*/
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expr const & get_choice(expr const & e, unsigned i);
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2013-08-25 01:02:38 +00:00
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}
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