fix(library/elaborator): missing condition
The elaborator was missing solutions because of the missing condition at is_simple_ho_match. This commit also adds a new test that exposes the problem. Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
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3 changed files with 42 additions and 1 deletions
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@ -739,7 +739,7 @@ class elaborator::imp {
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\brief See \c process_simple_ho_match
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\brief See \c process_simple_ho_match
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*/
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*/
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bool is_simple_ho_match(context const & ctx, expr const & a, expr const & b, bool is_lhs, unification_constraint const & c) {
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bool is_simple_ho_match(context const & ctx, expr const & a, expr const & b, bool is_lhs, unification_constraint const & c) {
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return is_meta_app(a) && are_args_vars(ctx, a) && closed(b) &&
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return is_meta_app(a) && !has_local_context(arg(a, 0)) && are_args_vars(ctx, a) && closed(b) &&
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(is_eq(c) || (is_lhs && !is_actual_upper(b)) || (!is_lhs && !is_actual_lower(b)));
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(is_eq(c) || (is_lhs && !is_actual_upper(b)) || (!is_lhs && !is_actual_lower(b)));
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}
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}
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16
tests/lean/exists4.lean
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16
tests/lean/exists4.lean
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@ -0,0 +1,16 @@
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Variable N : Type
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Variables a b c : N
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Variables P : N -> N -> N -> Bool
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Axiom H3 : P a b c
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Theorem T1 : exists x y z : N, P x y z := ExistsIntro::explicit N (fun x : N, exists y z : N, P x y z) a
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(ExistsIntro::explicit N _ b
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(ExistsIntro::explicit N (fun z : N, P a b z) c H3))
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Theorem T2 : exists x y z : N, P x y z := ExistsIntro a (ExistsIntro b (ExistsIntro c H3))
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Theorem T3 : exists x y z : N, P x y z := ExistsIntro _ (ExistsIntro _ (ExistsIntro _ H3))
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Theorem T4 (H : P a a b) : exists x y z, P x y z := ExistsIntro _ (ExistsIntro _ (ExistsIntro _ H))
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Show Environment 4
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25
tests/lean/exists4.lean.expected.out
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25
tests/lean/exists4.lean.expected.out
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@ -0,0 +1,25 @@
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Set: pp::colors
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Set: pp::unicode
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Assumed: N
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Assumed: a
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Assumed: b
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Assumed: c
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Assumed: P
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Assumed: H3
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Proved: T1
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Proved: T2
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Proved: T3
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Proved: T4
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Theorem T1 : ∃ x y z : N, P x y z :=
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ExistsIntro::explicit
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N
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(λ x : N, ∃ y z : N, P x y z)
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a
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(ExistsIntro::explicit
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N
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(λ x : N, if ((λ x::1 : N, if (P a x x::1) ⊥ ⊤) == (λ x : N, ⊤)) ⊥ ⊤)
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b
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(ExistsIntro::explicit N (λ z : N, P a b z) c H3))
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Theorem T2 : ∃ x y z : N, P x y z := ExistsIntro a (ExistsIntro b (ExistsIntro c H3))
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Theorem T3 : ∃ x y z : N, P x y z := ExistsIntro a (ExistsIntro b (ExistsIntro c H3))
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Theorem T4 (H : P a a b) : ∃ x y z : N, P x y z := ExistsIntro a (ExistsIntro a (ExistsIntro b H))
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