fix(library/blast/congruence_closure): bug at eq_congr_key_cmp::operator()(eq_congr_key const & k1, eq_congr_key const & k2)

It was not implementing the condition described in our paper.
This commit is contained in:
Leonardo de Moura 2016-01-16 19:33:24 -08:00
parent 7e11c5cf6e
commit 1d04160a9b
3 changed files with 68 additions and 20 deletions

View file

@ -614,33 +614,48 @@ int congruence_closure::compare_root(name const & R, expr e1, expr e2) const {
return expr_quick_cmp()(e1, e2);
}
int congruence_closure::eq_congr_key_cmp::operator()(eq_congr_key const & k1, eq_congr_key const & k2) const {
lean_assert(g_heq_based);
if (k1.m_hash != k2.m_hash)
return unsigned_cmp()(k1.m_hash, k2.m_hash);
lean_assert(is_app(k1.m_expr) && is_app(k2.m_expr));
expr const & f1 = app_fn(k1.m_expr);
expr const & a1 = app_arg(k1.m_expr);
expr const & f2 = app_fn(k2.m_expr);
expr const & a2 = app_arg(k2.m_expr);
int r = g_cc->compare_root(get_eq_name(), a1, a2);
if (r != 0) return r;
r = g_cc->compare_root(get_eq_name(), f1, f2);
if (r != 0) return r;
if (is_app(f1) && is_app(f2)) return 0; /* composite */
if (f1 == f2) return 0; /* identical functions */
expr f1_type = infer_type(f1);
expr f2_type = infer_type(f2);
if (is_def_eq(f1_type, f2_type)) return 0; /* same function type */
/** \brief Return true iff the given function application are congruent */
static bool is_eq_congruent(expr const & e1, expr const & e2) {
lean_assert(is_app(e1) && is_app(e2));
/* Given e1 := f a, e2 := g b */
expr f = app_fn(e1);
expr a = app_arg(e1);
expr g = app_fn(e2);
expr b = app_arg(e2);
if (g_cc->get_root(get_eq_name(), a) != g_cc->get_root(get_eq_name(), b)) {
/* a and b are not equivalent */
return false;
}
if (g_cc->get_root(get_eq_name(), f) != g_cc->get_root(get_eq_name(), g)) {
/* f and g are not equivalent */
return false;
}
if (is_def_eq(infer_type(f), infer_type(g))) {
/* Case 1: f and g have the same type, then we can create a congruence proof for f a == g b */
return true;
}
if (is_app(f) && is_app(g)) {
/* Case 2: f and g are congruent */
return is_eq_congruent(f, g);
}
/*
f1 and f2 are not applications and have different types.
f and g are not congruent nor they have the same type.
We can't generate a congruence proof in this case because the following lemma
hcongr : f1 == f2 -> a1 == a2 -> f1 a1 == f2 a2
is not provable. Remark: it is also not provable in MLTT, Coq and Agda (even if we assume UIP).
*/
return expr_quick_cmp()(f1, f2);
return false;
}
int congruence_closure::eq_congr_key_cmp::operator()(eq_congr_key const & k1, eq_congr_key const & k2) const {
lean_assert(g_heq_based);
if (k1.m_hash != k2.m_hash)
return unsigned_cmp()(k1.m_hash, k2.m_hash);
if (is_eq_congruent(k1.m_expr, k2.m_expr))
return 0;
return expr_quick_cmp()(k1.m_expr, k2.m_expr);
}
/* \brief Create a equality congruence table key.

View file

@ -0,0 +1,5 @@
set_option blast.strategy "cc"
example (C : nat → Type) (f : Π n, C n → C n) (n m : nat) (c : C n) (d : C m) :
f n == f m → c == d → f n c == f m d :=
by blast

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@ -0,0 +1,28 @@
blast_cc_not_provable.lean:5:0: error: blast tactic failed
strategy 'cc' failed, no proof found, final state:
C : → Type,
n m : ,
f : Π (n : ), C n → C n,
c : C n,
d : C m,
H.6 : f n == f m,
H.7 : c == d
⊢ f n c == f m d
-------
proof state:
C : → Type,
f : Π (n : ), C n → C n,
n m : ,
c : C n,
d : C m
⊢ f n == f m → c == d → f n c == f m d
blast_cc_not_provable.lean:5:0: error: don't know how to synthesize placeholder
C : → Type,
f : Π (n : ), C n → C n,
n m : ,
c : C n,
d : C m
⊢ f n == f m → c == d → f n c == f m d
blast_cc_not_provable.lean:5:0: error: failed to add declaration 'example' to environment, value has metavariables
remark: set 'formatter.hide_full_terms' to false to see the complete term
?M_1