feat(library/data/list/sort): prove that (sort R l) is strongly_sorted

This commit is contained in:
Leonardo de Moura 2015-08-09 21:22:53 -07:00
parent 5ca37dace0
commit 2a22c75e52

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@ -5,7 +5,7 @@ Authors: Leonardo de Moura
Naive sort for lists
-/
import data.list.comb data.list.set data.list.perm logic.connectives
import data.list.comb data.list.set data.list.perm data.list.sorted logic.connectives
namespace list
open decidable nat
@ -70,9 +70,9 @@ assume h : b ∈ l, min_core_lemma to tr rf a (or.inl h)
lemma min_core_le {l : list A} (a : A) : R (min_core R l a) a :=
min_core_lemma to tr rf a (or.inr rfl)
lemma min_lemma : ∀ {a : A} {l} (h : l ≠ nil), all l (R (min R l h))
| a [] h := absurd rfl h
| a (b::l) h :=
lemma min_lemma : ∀ {l} (h : l ≠ nil), all l (R (min R l h))
| [] h := absurd rfl h
| (b::l) h :=
all_of_forall (take x, suppose x ∈ b::l,
or.elim (eq_or_mem_of_mem_cons this)
(suppose x = b,
@ -146,4 +146,22 @@ lemma sort_aux_perm : ∀ {n : nat} {l : list A} (h : length l = n), sort_aux R
lemma sort_perm (l : list A) : sort R l ~ l :=
sort_aux_perm R rfl
lemma strongly_sorted_sort_aux : ∀ {n : nat} {l : list A} (h : length l = n), strongly_sorted R (sort_aux R n l h)
| 0 l h := !strongly_sorted.base
| (succ n) l h :=
let m := min R l (ne_nil h) in
assert leq : length (erase m l) = n, from sort_aux_lemma R h,
assert ss : strongly_sorted R (sort_aux R n (erase m l) leq), from strongly_sorted_sort_aux leq,
assert all l (R m), from min_lemma to tr rf (ne_nil h),
assert hall : all (sort_aux R n (erase m l) leq) (R m), from
all_of_forall (take x,
suppose x ∈ sort_aux R n (erase m l) leq,
have x ∈ erase m l, from mem_perm (sort_aux_perm R leq) this,
have x ∈ l, from mem_of_mem_erase this,
show R m x, from of_mem_of_all this `all l (R m)`),
strongly_sorted.step hall ss
lemma strongly_sorted_sort (to : total R) (tr : transitive R) (rf : reflexive R) (l : list A) : strongly_sorted R (sort R l) :=
@strongly_sorted_sort_aux _ _ _ _ to tr rf (length l) l rfl
end list