feat(library/algebra/ordered_group): define abs in terms of max, make some theorems constructively valid

This commit is contained in:
Jeremy Avigad 2015-06-29 14:39:36 +10:00
parent b19331f28f
commit 3bf18c174e

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@ -476,6 +476,41 @@ section
theorem max_eq_neg_min_neg_neg : max a b = - min (-a) (-b) :=
by rewrite [min_neg_neg, neg_neg]
/- absolute value -/
variables {a b c}
definition abs (a : A) : A := max a (-a)
theorem abs_of_nonneg (H : a ≥ 0) : abs a = a :=
have H' : -a ≤ a, from le.trans (neg_nonpos_of_nonneg H) H,
max_eq_left H'
theorem abs_of_pos (H : a > 0) : abs a = a :=
abs_of_nonneg (le_of_lt H)
theorem abs_of_nonpos (H : a ≤ 0) : abs a = -a :=
have H' : a ≤ -a, from le.trans H (neg_nonneg_of_nonpos H),
max_eq_right H'
theorem abs_of_neg (H : a < 0) : abs a = -a := abs_of_nonpos (le_of_lt H)
theorem abs_zero : abs 0 = (0:A) := abs_of_nonneg (le.refl _)
theorem abs_neg (a : A) : abs (-a) = abs a :=
by rewrite [↑abs, max.comm, neg_neg]
theorem abs_pos_of_pos (H : a > 0) : abs a > 0 :=
by rewrite (abs_of_pos H); exact H
theorem abs_pos_of_neg (H : a < 0) : abs a > 0 :=
!abs_neg ▸ abs_pos_of_pos (neg_pos_of_neg H)
theorem abs_sub (a b : A) : abs (a - b) = abs (b - a) :=
by rewrite [-neg_sub, abs_neg]
theorem ne_zero_of_abs_ne_zero {a : A} (H : abs a ≠ 0) : a ≠ 0 :=
assume Ha, H (Ha⁻¹ ▸ abs_zero)
end
/- linear ordered group with decidable order -/
@ -513,28 +548,6 @@ section
have H2: a < 0, from H ▸ neg_neg_of_pos H1,
absurd H1 (lt.asymm H2))
definition abs (a : A) : A := if 0 ≤ a then a else -a
theorem abs_of_nonneg (H : a ≥ 0) : abs a = a := if_pos H
theorem abs_of_pos (H : a > 0) : abs a = a := if_pos (le_of_lt H)
theorem abs_of_neg (H : a < 0) : abs a = -a := if_neg (not_le_of_gt H)
theorem abs_zero : abs 0 = (0:A) := abs_of_nonneg (le.refl _)
theorem abs_of_nonpos (H : a ≤ 0) : abs a = -a :=
decidable.by_cases
(assume H1 : a = 0, by rewrite [H1, abs_zero, neg_zero])
(assume H1 : a ≠ 0,
have H2 : a < 0, from lt_of_le_of_ne H H1,
abs_of_neg H2)
theorem abs_neg (a : A) : abs (-a) = abs a :=
or.elim (le.total 0 a)
(assume H1 : 0 ≤ a, by rewrite [abs_of_nonpos (neg_nonpos_of_nonneg H1), neg_neg, abs_of_nonneg H1])
(assume H1 : a ≤ 0, by rewrite [abs_of_nonneg (neg_nonneg_of_nonpos H1), abs_of_nonpos H1])
theorem abs_nonneg (a : A) : abs a ≥ 0 :=
or.elim (le.total 0 a)
(assume H : 0 ≤ a, by rewrite (abs_of_nonneg H); exact H)
@ -561,18 +574,9 @@ section
theorem abs_eq_zero_iff_eq_zero (a : A) : abs a = 0 ↔ a = 0 :=
iff.intro eq_zero_of_abs_eq_zero (assume H, congr_arg abs H ⬝ !abs_zero)
theorem abs_pos_of_pos (H : a > 0) : abs a > 0 :=
by rewrite (abs_of_pos H); exact H
theorem abs_pos_of_neg (H : a < 0) : abs a > 0 :=
!abs_neg ▸ abs_pos_of_pos (neg_pos_of_neg H)
theorem abs_pos_of_ne_zero (H : a ≠ 0) : abs a > 0 :=
or.elim (lt_or_gt_of_ne H) abs_pos_of_neg abs_pos_of_pos
theorem abs_sub (a b : A) : abs (a - b) = abs (b - a) :=
by rewrite [-neg_sub, abs_neg]
theorem abs.by_cases {P : A → Prop} {a : A} (H1 : P a) (H2 : P (-a)) : P (abs a) :=
or.elim (le.total 0 a)
(assume H : 0 ≤ a, (abs_of_nonneg H)⁻¹ ▸ H1)
@ -584,9 +588,6 @@ section
theorem abs_lt_of_lt_of_neg_lt (H1 : a < b) (H2 : -a < b) : abs a < b :=
abs.by_cases H1 H2
theorem ne_zero_of_abs_ne_zero {a : A} (H : abs a ≠ 0) : a ≠ 0 :=
assume Ha, H (Ha⁻¹ ▸ abs_zero)
-- the triangle inequality
section
private lemma aux1 {a b : A} (H1 : a + b ≥ 0) (H2 : a ≥ 0) : abs (a + b) ≤ abs a + abs b :=
@ -636,7 +637,6 @@ section
abs (a + b) = abs (-a + -b) : by rewrite [-abs_neg, neg_add]
... ≤ abs (-a) + abs (-b) : aux2 H5
... = abs a + abs b : by rewrite *abs_neg)
end
theorem abs_sub_abs_le_abs_sub (a b : A) : abs a - abs b ≤ abs (a - b) :=
have H1 : abs a - abs b + abs b ≤ abs (a - b) + abs b, from
@ -656,5 +656,6 @@ section
apply le.refl
end
end
end
end algebra