test(tests/lean/run): pre-quotient experiment
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tests/lean/run/pquot.lean
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tests/lean/run/pquot.lean
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import logic.cast data.list data.sigma
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-- The (pre-)quotient type kernel extension would add the following constants
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-- quot, pquot.mk, pquot.eqv and pquot.rec
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-- and a computational rule, which we call pquot.comp here.
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-- Note that, these constants do not assume the environment contains =
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constant pquot.{l} {A : Type.{l}} (R : A → A → Prop) : Type.{l}
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constant pquot.abs {A : Type} (R : A → A → Prop) : A → pquot R
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-- pquot.eqv is a way to say R a b → (pquot.abs R a) = (pquot.abs R b) without mentioning equality
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constant pquot.eqv {A : Type} (R : A → A → Prop) {a b : A} : R a b → ∀ (P : pquot R → Prop), P (pquot.abs R a) → P (pquot.abs R b)
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constant pquot.rec {A : Type} {R : A → A → Prop} {C : pquot R → Type}
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(f : Π a, C (pquot.abs R a))
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-- sound is essentially saying: ∀ (a b : A) (H : R a b), f a == f b
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-- H makes sure we can only define a function on (quot R) if for all a b : A
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-- R a b → f a == f b
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(sound : ∀ a b, R a b → ∀ P : (Π (q : pquot R), C q → Prop), P (pquot.abs R a) (f a) → P (pquot.abs R b) (f b))
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(q : pquot R)
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: C q
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-- We would also get the following computational rule:
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-- pquot.rec R H₁ H₂ (pquot.abs R a) ==> H₁ a
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constant pquot.comp {A : Type} {R : A → A → Prop} {C : pquot R → Type}
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(f : Π a, C (pquot.abs R a))
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(sound : ∀ a b, R a b → ∀ P : (Π (q : pquot R), C q → Prop), P (pquot.abs R a) (f a) → P (pquot.abs R b) (f b))
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(a : A)
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-- In the implementation this would be a computational rule
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: pquot.rec f sound (pquot.abs R a) = f a
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-- If the environment contains = and ==, then we can define
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definition pquot.eq {A : Type} (R : A → A → Prop) {a b : A} (H : R a b) : pquot.abs R a = pquot.abs R b :=
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have aux : ∀ (P : pquot R → Prop), P (pquot.abs R a) → P (pquot.abs R b), from
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pquot.eqv R H,
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aux (λ x : pquot R, pquot.abs R a = x) rfl
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definition pquot.rec_on {A : Type} {R : A → A → Prop} {C : pquot R → Type}
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(q : pquot R)
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(f : Π a, C (pquot.abs R a))
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(sound : ∀ (a b : A), R a b → f a == f b)
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: C q :=
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pquot.rec f
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(λ (a b : A) (H : R a b) (P : Π (q : pquot R), C q → Prop) (Ha : P (pquot.abs R a) (f a)),
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have aux₁ : f a == f b, from sound a b H,
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have aux₂ : pquot.abs R a = pquot.abs R b, from pquot.eq R H,
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have aux₃ : ∀ (c₁ c₂ : C (pquot.abs R a)) (e : c₁ == c₂), P (pquot.abs R a) c₁ → P (pquot.abs R a) c₂, from
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λ c₁ c₂ e H, eq.rec_on (heq.to_eq e) H,
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have aux₄ : ∀ (c₁ : C (pquot.abs R a)) (c₂ : C (pquot.abs R b)) (e : c₁ == c₂), P (pquot.abs R a) c₁ → P (pquot.abs R b) c₂, from
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eq.rec_on aux₂ aux₃,
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show P (pquot.abs R b) (f b), from
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aux₄ (f a) (f b) aux₁ Ha)
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q
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definition pquot.lift {A : Type} {R : A → A → Prop} {B : Type}
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(f : A → B)
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(sound : ∀ (a b : A), R a b → f a = f b)
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(q : pquot R)
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: B :=
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pquot.rec_on q f (λ (a b : A) (H : R a b), heq.from_eq (sound a b H))
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theorem pquot.induction_on {A : Type} {R : A → A → Prop} {P : pquot R → Prop}
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(q : pquot R)
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(f : ∀ a, P (pquot.abs R a))
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: P q :=
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pquot.rec_on q f (λ (a b : A) (H : R a b),
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have aux₁ : pquot.abs R a = pquot.abs R b, from pquot.eq R H,
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have aux₂ : P (pquot.abs R a) = P (pquot.abs R b), from congr_arg P aux₁,
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have aux₃ : cast aux₂ (f a) = f b, from proof_irrel (cast aux₂ (f a)) (f b),
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show f a == f b, from
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@cast_to_heq _ _ _ _ aux₂ aux₃)
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theorem pquot.abs.surjective {A : Type} {R : A → A → Prop} : ∀ q : pquot R, ∃ x : A, pquot.abs R x = q :=
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take q, pquot.induction_on q (take a, exists_intro a rfl)
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definition pquot.exact {A : Type} (R : A → A → Prop) :=
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∀ a b : A, pquot.abs R a = pquot.abs R b → R a b
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-- Definable quotient
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structure dquot {A : Type} (R : A → A → Prop) :=
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mk :: (rep : pquot R → A)
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(complete : ∀a, R (rep (pquot.abs R a)) a)
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-- (stable : ∀q, pquot.abs R (rep q) = q)
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structure is_equiv {A : Type} (R : A → A → Prop) :=
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mk :: (refl : ∀x, R x x)
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(symm : ∀{x y}, R x y → R y x)
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(trans : ∀{x y z}, R x y → R y z → R x z)
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-- Definiable quotients are exact if R is an equivalence relation
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theorem quot.exact {A : Type} {R : A → A → Prop} (eqv : is_equiv R) (q : dquot R) : pquot.exact R :=
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λ (a b : A) (H : pquot.abs R a = pquot.abs R b),
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have H₁ : pquot.abs R a = pquot.abs R a → R (dquot.rep q (pquot.abs R a)) (dquot.rep q (pquot.abs R a)),
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from λH, is_equiv.refl eqv _,
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have H₂ : pquot.abs R a = pquot.abs R b → R (dquot.rep q (pquot.abs R a)) (dquot.rep q (pquot.abs R b)),
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from eq.subst H H₁,
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have H₃ : R (dquot.rep q (pquot.abs R a)) (dquot.rep q (pquot.abs R b)),
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from H₂ H,
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have H₄ : R a (dquot.rep q (pquot.abs R a)), from is_equiv.symm eqv (dquot.complete q a),
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have H₅ : R (dquot.rep q (pquot.abs R b)) b, from dquot.complete q b,
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is_equiv.trans eqv H₄ (is_equiv.trans eqv H₃ H₅)
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