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test(tests/lean/run): disable recursor tactic and add tests for unit+cc

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Leonardo de Moura 2015-11-25 06:43:48 -08:00
parent ca71a2eb12
commit 84b54ad027
4 changed files with 20 additions and 3 deletions
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2
tests/lean/run/blast24.lean
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-- Basic (propositional) forward chaining with clauses
constants (A B C D E : Prop)
set_option blast.recursor false
definition lemma1 : A → (A ∨ B → C) → C := by blast
definition lemma2 : B → (A ∨ B → C) → C := by blast
definition lemma3 : A → B → (A → B ∨ C → D) → D := by blast
definition lemma4 : A → B → (A → B ∨ C ∨ C → D) → D := by blast
definition lemma5 : A → B → (E ∨ A ∨ E → E ∨ B ∨ C ∨ C → D) → D := by blast
definition lemma6 : A → (A → B → C) → ¬ C → ¬ B := by blast
definition lemma7 : ¬ D → B → (A → E ∨ B ∨ C ∨ C → D) → ¬ A := by blast
definition lemma8 : ¬ D → B → (A ∨ E → E ∨ B ∨ C ∨ C → D) → ¬ (A ∨ E) := by blast

2
tests/lean/run/blast25.lean
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-- Basic (propositional) forward chaining with conjunctive conclusions
constants (A B C D E : Prop)
set_option pp.all true
set_option blast.recursor false
definition lemma1 : B → (A → (¬ B) ∧ C) → ¬ A := by blast
definition lemma2 : ¬ B → (A → B ∧ C) → ¬ A := by blast

2
tests/lean/run/blast26.lean
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-- Basic (propositional) forward chaining with disjunctive antecedents and conjunctive conclusions
constants (A B C D E F : Prop)
set_option blast.recursor false
definition lemma1 : B → (A ∨ E → (¬ B) ∧ C) → ¬ (A ∨ E) := by blast
definition lemma2 : ¬ B → (A ∨ E → B ∧ C) → ¬ (A ∨ E) := by blast
definition lemma3 : A → ¬ D → (A ∨ E → B → C ∧ D) → ¬ B := by blast
definition lemma4 : A → ¬ E → (A → B → E ∧ F) → ¬ B := by blast
definition lemma5 : (A → B) → ¬ B → ¬ A := by blast
definition lemma6 : (A → B ∧ C) → ¬ B → ¬ A := by blast

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tests/lean/run/blast27.lean Normal file
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-- Basic (propositional) forward chaining with conjunctive conclusions
constants (a b c d e : nat)
constants (p : nat → Prop)
constants (q : nat → nat → Prop)
constants (f : nat → nat)
set_option blast.recursor false
set_option blast.subst false
definition lemma1 : a = d → b = e → p b → (p a → (¬ p e) ∧ p c) → ¬ p d := by blast
definition lemma2a : ¬ p b → (p d → p b ∧ p c) → d = e → e = a → ¬ p a := by blast
definition lemma2b : ¬ p (f b) → (p (f a) → p (f d) ∧ p (f c)) → b = d → ¬ p (f a) := by blast
definition lemma3 : p (f (f b)) → (p (f a) → p (f c) ∧ (¬ p (f (f (f (f b)))))) → b = f b → ¬ p (f a) := by blast
definition lemma4a : b = f b → ¬ p (f (f b)) → (p a → q c c ∧ p (f (f (f (f (f b)))))) → ¬ p a := by blast
definition lemma4b : b = f b → ¬ p (f (f b)) → (p a → q c c ∧ q e c ∧ q d e ∧ p (f (f (f (f (f b))))) ∧ q e d) → ¬ p a :=
by blast
definition lemma5 : p b → (p (f a) → (¬ p b) ∧ p e ∧ p c) → ¬ p (f a) := by blast
definition lemma6 : ¬ (q b a) → d = a → (p a → p e ∧ (q b d) ∧ p c) → ¬ p a := by blast