Assumed: x Type u+3 ⊔ m+2 ⊔ 3 Assumed: f Type u+10 → Type Type Type 5 Type u+3 ⊔ m+2 ⊔ 3 Type u+1 ⊔ m+1 Type u+3 Type u+4 Type u+1 ⊔ m+1 Type u+1 ⊔ m+1 ⊔ 4 Type u+1 ⊔ m ⊔ 3 Type u+2 ⊔ m+1 ⊔ 4 Type u → Type 5 Type u+1 ⊔ 6 Type m+1 ⊔ 4 ⊔ u+6 Type m ⊔ 3 → Type u → Type 5 Type m+1 ⊔ 6 ⊔ u+1 Type u