(* This example demonstrates how to specify a proof skeleton that contains "holes" that must be filled using user-defined tactics. *) (** -- Define a simple tactic using Lua auto = REPEAT(ORELSE(assumption_tac, conj_tac, conj_hyp_tac)) **) (* The (by [tactic]) expression is essentially creating a "hole" and associating a "hint" to it. The "hint" is a tactic that should be used to fill the "hole". In the following example, we use the tactic "auto" defined by the Lua code above. The (show [expr] by [tactic]) expression is also creating a "hole" and associating a "hint" to it. The expression [expr] after the shows is fixing the type of the "hole" *) Theorem T1 (A B : Bool) : A /\ B -> B /\ A := fun assumption : A /\ B, let lemma1 : A := (by auto), lemma2 : B := (by auto) in (show B /\ A by auto) Show Environment 1. (* Show proof for the previous theorem *) (* When hints are not provided, the user must fill the (remaining) holes using tactic command sequences. Each hole must be filled with a tactic command sequence that terminates with the command 'done' and successfully produces a proof term for filling the hole. Here is the same example without hints This style is more convenient for interactive proofs *) Theorem T2 (A B : Bool) : A /\ B -> B /\ A := fun assumption : A /\ B, let lemma1 : A := _, (* first hole *) lemma2 : B := _ (* second hole *) in _. (* third hole *) apply auto. done. (* tactic command sequence for the first hole *) apply auto. done. (* tactic command sequence for the second hole *) apply auto. done. (* tactic command sequence for the third hole *) (* In the following example, instead of using the "auto" tactic, we apply a sequence of even simpler tactics. *) Theorem T3 (A B : Bool) : A /\ B -> B /\ A := fun assumption : A /\ B, let lemma1 : A := _, (* first hole *) lemma2 : B := _ (* second hole *) in _. (* third hole *) apply conj_hyp_tac. apply assumption_tac. done. (* tactic command sequence for the first hole *) apply conj_hyp_tac. apply assumption_tac. done. (* tactic command sequence for the second hole *) apply conj_tac. apply assumption_tac. done. (* tactic command sequence for the third hole *) (* We can also mix the two styles (hints and command sequences) *) Theorem T4 (A B : Bool) : A /\ B -> B /\ A := fun assumption : A /\ B, let lemma1 : A := _, (* first hole *) lemma2 : B := _ (* second hole *) in (show B /\ A by auto). apply conj_hyp_tac. apply assumption_tac. done. (* tactic command sequence for the first hole *) apply conj_hyp_tac. apply assumption_tac. done. (* tactic command sequence for the second hole *)