lean2/examples/lean/tactic1.lean
Leonardo de Moura 9f08156a73 feat(frontends/lean/parser): combine Echo and Show commands into the 'print' command
Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
2014-01-05 11:03:35 -08:00

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-- This example demonstrates how to specify a proof skeleton that contains
-- "holes" that must be filled using user-defined tactics.
(*
-- Import useful macros for creating tactics
import("tactic.lua")
-- Define a simple tactic using Lua
auto = Repeat(OrElse(assumption_tac(), conj_tac(), conj_hyp_tac()))
conj_hyp = conj_hyp_tac()
conj = conj_tac()
*)
-- The (by [tactic]) expression is essentially creating a "hole" and associating a "hint" to it.
-- The "hint" is a tactic that should be used to fill the "hole".
-- In the following example, we use the tactic "auto" defined by the Lua code above.
--
-- The (show [expr] by [tactic]) expression is also creating a "hole" and associating a "hint" to it.
-- The expression [expr] after the shows is fixing the type of the "hole"
Theorem T1 (A B : Bool) : A /\ B -> B /\ A :=
fun assumption : A /\ B,
let lemma1 : A := (by auto),
lemma2 : B := (by auto)
in (show B /\ A by auto)
print Environment 1. -- print proof for the previous theorem
-- When hints are not provided, the user must fill the (remaining) holes using tactic command sequences.
-- Each hole must be filled with a tactic command sequence that terminates with the command 'done' and
-- successfully produces a proof term for filling the hole. Here is the same example without hints
-- This style is more convenient for interactive proofs
Theorem T2 (A B : Bool) : A /\ B -> B /\ A :=
fun assumption : A /\ B,
let lemma1 : A := _, -- first hole
lemma2 : B := _ -- second hole
in _. -- third hole
auto. done. -- tactic command sequence for the first hole
auto. done. -- tactic command sequence for the second hole
auto. done. -- tactic command sequence for the third hole
-- In the following example, instead of using the "auto" tactic, we apply a sequence of even simpler tactics.
Theorem T3 (A B : Bool) : A /\ B -> B /\ A :=
fun assumption : A /\ B,
let lemma1 : A := _, -- first hole
lemma2 : B := _ -- second hole
in _. -- third hole
conj_hyp. exact. done. -- tactic command sequence for the first hole
conj_hyp. exact. done. -- tactic command sequence for the second hole
conj. exact. done. -- tactic command sequence for the third hole
-- We can also mix the two styles (hints and command sequences)
Theorem T4 (A B : Bool) : A /\ B -> B /\ A :=
fun assumption : A /\ B,
let lemma1 : A := _, -- first hole
lemma2 : B := _ -- second hole
in (show B /\ A by auto).
auto. done. -- tactic command sequence for the first hole
auto. done. -- tactic command sequence for the second hole