41 lines
1.5 KiB
Text
41 lines
1.5 KiB
Text
constant f : Π {A : Type}, A → A → A
|
|
variables a b c : nat
|
|
variables H : a = b
|
|
|
|
set_option pp.all true
|
|
|
|
#replace f a a, [a], [b]
|
|
#replace f (f a b) b, [a,b], [b,a]
|
|
|
|
variables x y : bool
|
|
|
|
-- [nat] and [bool] are instances of the telescope (A : Type),
|
|
-- but the resulting expression is type incorrect.
|
|
-- Thus, #replace correctly detects the error.
|
|
#replace f a a, [nat], [bool] -- Error
|
|
-- An error is not detected in the following one,
|
|
-- since there is no telescope s.t., [a] and [x] are instances of.
|
|
#replace f a a, [a], [x]
|
|
-- The following should work, [nat, a] and [bool, x] are instances
|
|
-- of the telescope (A : Type, a : A), and the result is type correct
|
|
#replace f a a, [nat, a], [bool, x]
|
|
|
|
variable p : nat → Prop
|
|
variable H1 : p a
|
|
|
|
-- [b] and [a] are instances of the telescope (x : nat),
|
|
-- but the resulting expression is type incorrect.
|
|
-- Thus, #replace correctly detects the error.
|
|
#replace @eq.rec nat a (λ x : nat, p x) H1 b H, [b], [a] -- Error
|
|
-- There is no telescope s.t. [H] and [eq.refl a] are instances of.
|
|
#replace @eq.rec nat a (λ x : nat, p x) H1 b H, [H], [eq.refl a]
|
|
-- [b, H] and [a, eq.refl a] are both instances of the telescope
|
|
-- (x : nat, H : a = x), and the resulting expression is type correct
|
|
#replace @eq.rec nat a (λ x : nat, p x) H1 b H, [b, H], [a, eq.refl a]
|
|
|
|
constant bv : nat → Type₁
|
|
|
|
variables v₁ v₂ : bv 10
|
|
|
|
#replace v₁ = v₂, [(10:nat)], [(11:nat)] -- Error
|
|
#replace (λ v₁ v₂ : bv 10, v₁ = v₂), [(10:nat)], [(11:nat)]
|