691893258d
The new hash code has the property that given expr_cell * c1 and expr_cell * c2, if c1 != c2 then there is a high propbability that c1->hash_alloc() != c2->hash_alloc(). The structural hash code hash() does not have this property because we may have c1 != c2, but c1 and c2 are structurally equal. The new hash code is only compatible with pointer equality. By compatible we mean, if c1 == c2, then c1->hash_alloc() == c2->hash_alloc(). This property is obvious because hash_alloc() does not have side-effects. The test tests/lua/big.lua exposes the problem fixed by this commit. Signed-off-by: Leonardo de Moura <leonardo@microsoft.com> |
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| .. | ||
| CMakeLists.txt | ||
| coercion.h | ||
| frontend.cpp | ||
| frontend.h | ||
| frontend_elaborator.cpp | ||
| frontend_elaborator.h | ||
| notation.cpp | ||
| notation.h | ||
| operator_info.cpp | ||
| operator_info.h | ||
| parser.cpp | ||
| parser.h | ||
| pp.cpp | ||
| pp.h | ||
| scanner.cpp | ||
| scanner.h | ||