lean2/examples/lean/set.lean
Leonardo de Moura f18360a294 doc(examples/lean/set): prove antisymmetry for subset relation
Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
2013-12-26 22:37:44 -08:00

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(**
-- import macros for, assume, mp, ...
import("macros.lua")
**)
Definition Set (A : Type) : Type := A → Bool
Definition element {A : Type} (x : A) (s : Set A) := s x
Infix 60 ∈ : element
Definition subset {A : Type} (s1 : Set A) (s2 : Set A) := ∀ x, x ∈ s1 ⇒ x ∈ s2
Infix 50 ⊆ : subset
Theorem SubsetTrans (A : Type) : ∀ s1 s2 s3 : Set A, s1 ⊆ s2 ⇒ s2 ⊆ s3 ⇒ s1 ⊆ s3 :=
for s1 s2 s3, assume (H1 : s1 ⊆ s2) (H2 : s2 ⊆ s3),
show s1 ⊆ s3,
for x, assume Hin : x ∈ s1,
show x ∈ s3,
let L1 : x ∈ s2 := mp (instantiate H1 x) Hin
in mp (instantiate H2 x) L1
Theorem SubsetExt (A : Type) : ∀ s1 s2 : Set A, (∀ x, x ∈ s1 = x ∈ s2) ⇒ s1 = s2 :=
for s1 s2, assume (H : ∀ x, x ∈ s1 = x ∈ s2),
Abst (fun x, instantiate H x)
Theorem SubsetAntiSymm (A : Type) : ∀ s1 s2 : Set A, s1 ⊆ s2 ⇒ s2 ⊆ s1 ⇒ s1 = s2 :=
for s1 s2, assume (H1 : s1 ⊆ s2) (H2 : s2 ⊆ s1),
show s1 = s2,
MP (show (∀ x, x ∈ s1 = x ∈ s2) ⇒ s1 = s2,
instantiate (SubsetExt A) s1 s2)
(show (∀ x, x ∈ s1 = x ∈ s2),
for x, show x ∈ s1 = x ∈ s2,
let L1 : x ∈ s1 ⇒ x ∈ s2 := instantiate H1 x,
L2 : x ∈ s2 ⇒ x ∈ s1 := instantiate H2 x
in ImpAntisym L1 L2)
(* Compact (but less readable) version of the previous theorem *)
Theorem SubsetAntiSymm2 (A : Type) : ∀ s1 s2 : Set A, s1 ⊆ s2 ⇒ s2 ⊆ s1 ⇒ s1 = s2 :=
for s1 s2, assume H1 H2,
MP (instantiate (SubsetExt A) s1 s2)
(for x, ImpAntisym (instantiate H1 x) (instantiate H2 x))