2ddcc32c1d
It should match the precedence of the implication '=>'. Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
12 lines
470 B
Text
12 lines
470 B
Text
Variable C {A B : Type} (H : A = B) (a : A) : B
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Variable D {A A' : Type} {B : A -> Type} {B' : A' -> Type} (H : (Pi x : A, B x) = (Pi x : A', B' x)) : A = A'
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Variable R {A A' : Type} {B : A -> Type} {B' : A' -> Type} (H : (Pi x : A, B x) = (Pi x : A', B' x)) (a : A) :
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(B a) = (B' (C (D H) a))
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Theorem R2 : Pi (A1 A2 B1 B2 : Type), ((A1 -> B1) = (A2 -> B2)) -> A1 -> (B1 = B2) :=
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fun A1 A2 B1 B2 H a, R H a
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Set pp::implicit true
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Show Environment 7.
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