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lean2/tests/lean/elab1.lean.expected.out
Leonardo de Moura 9c60eed93c refactor(kernel/metavar): avoid using unique names for default metavariable prefix 
The problem is that unique names depend on the order compilation units are initialized. The order of initialization is not specified by the C++ standard. Then, different compilers (or even the same compiler) may produce different initialization orders, and consequently the metavariable prefix is going to be different for different builds. This is not a bug, but it makes unit tests to fail since the output produced by different builds is different for the same input file.
Avoiding unique name feature in the default metavariable prefix avoids this problem.

Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
2013-11-07 10:16:25 -08:00

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Set: pp::colors
Set: pp::unicode
Assumed: f
Failed to solve
⊢ (?M::1 ≈ λ x : ℕ, x) ⊕ (?M::1 ≈ nat_to_int) ⊕ (?M::1 ≈ nat_to_real)
(line: 4: pos: 8) Coercion for
10
Failed to solve
⊢ Bool ≺ ℕ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℕ ≺ ?M::0
Substitution
⊢ (?M::5[inst:0 (10)]) 10 ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
x : ℕ ⊢ λ x : ℕ, ℕ ≈ ?M::5
Destruct/Decompose
x : ℕ ⊢ ℕ ≈ ?M::5 x
Destruct/Decompose
⊢ ℕ → ℕ ≈ Π x : ?M::4, ?M::5 x
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5 x
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℕ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ λ x : ℕ, x
Assumption 0
Failed to solve
⊢ Bool ≺ ℤ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℤ ≺ ?M::0
Substitution
⊢ (?M::5[inst:0 (10)]) 10 ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
_ : ℕ ⊢ λ x : ℕ, ℤ ≈ ?M::5
Destruct/Decompose
_ : ℕ ⊢ ℤ ≈ ?M::5 _
Destruct/Decompose
⊢ ℕ → ℤ ≈ Π x : ?M::4, ?M::5 x
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5 x
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℤ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ nat_to_int
Assumption 1
Failed to solve
⊢ Bool ≺ ℝ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℝ ≺ ?M::0
Substitution
⊢ (?M::5[inst:0 (10)]) 10 ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
_ : ℕ ⊢ λ x : ℕ, ℝ ≈ ?M::5
Destruct/Decompose
_ : ℕ ⊢ ℝ ≈ ?M::5 _
Destruct/Decompose
⊢ ℕ → ℝ ≈ Π x : ?M::4, ?M::5 x
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5 x
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℝ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ nat_to_real
Assumption 2
Assumed: g
Error (line: 7, pos: 8) unexpected metavariable occurrence
Assumed: h
Failed to solve
x : ?M::0, A : Type ⊢ ?M::0[lift:0:2] ≺ A
(line: 11: pos: 27) Type of argument 2 must be convertible to the expected type in the application of
h
with arguments:
A
x
Assumed: my_eq
Failed to solve
A : Type, B : Type, a : ?M::0, b : ?M::1, C : Type ⊢ ?M::0[lift:0:3] ≺ C
(line: 15: pos: 51) Type of argument 2 must be convertible to the expected type in the application of
my_eq
with arguments:
C
a
b
Assumed: a
Assumed: b
Assumed: H
Error (line: 20, pos: 28) unexpected metavariable occurrence
Failed to solve
⊢ b ≈ a
Substitution
⊢ b ≈ ?M::3
Destruct/Decompose
⊢ b == b ≺ ?M::3 == ?M::4
(line: 22: pos: 22) Type of argument 6 must be convertible to the expected type in the application of
Trans::explicit
with arguments:
?M::1
?M::2
?M::3
?M::4
Refl a
Refl b
Assignment
⊢ a ≈ ?M::3
Destruct/Decompose
⊢ a == a ≺ ?M::2 == ?M::3
(line: 22: pos: 22) Type of argument 5 must be convertible to the expected type in the application of
Trans::explicit
with arguments:
?M::1
?M::2
?M::3
?M::4
Refl a
Refl b
Failed to solve
⊢ (?M::0 ≈ Type) ⊕ (?M::0 ≈ Type 1) ⊕ (?M::0 ≈ Type 2) ⊕ (?M::0 ≈ Type M) ⊕ (?M::0 ≈ Type U)
Destruct/Decompose
⊢ Type ≺ ?M::0
(line: 24: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Failed to solve
⊢ (?M::1 ≈ Type 1) ⊕ (?M::1 ≈ Type 2) ⊕ (?M::1 ≈ Type 3) ⊕ (?M::1 ≈ Type M) ⊕ (?M::1 ≈ Type U)
Destruct/Decompose
⊢ Type 1 ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type
Assumption 0
Failed to solve
⊢ Type 1 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 1
Assumption 1
Failed to solve
⊢ Type 2 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 2
Assumption 2
Failed to solve
⊢ Type 3 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 3
Assumption 3
Failed to solve
⊢ Type M ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M
Assumption 4
Failed to solve
⊢ Type U ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U
Assumption 5
Failed to solve
⊢ (?M::1 ≈ Type 2) ⊕ (?M::1 ≈ Type 3) ⊕ (?M::1 ≈ Type 4) ⊕ (?M::1 ≈ Type M) ⊕ (?M::1 ≈ Type U)
Destruct/Decompose
⊢ Type 2 ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type 1
Assumption 6
Failed to solve
⊢ Type 2 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 2
Assumption 7
Failed to solve
⊢ Type 3 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 3
Assumption 8
Failed to solve
⊢ Type 4 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 4
Assumption 9
Failed to solve
⊢ Type M ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M
Assumption 10
Failed to solve
⊢ Type U ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U
Assumption 11
Failed to solve
⊢ (?M::1 ≈ Type 3) ⊕ (?M::1 ≈ Type 4) ⊕ (?M::1 ≈ Type 5) ⊕ (?M::1 ≈ Type M) ⊕ (?M::1 ≈ Type U)
Destruct/Decompose
⊢ Type 3 ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type 2
Assumption 12
Failed to solve
⊢ Type 3 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 3
Assumption 13
Failed to solve
⊢ Type 4 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 4
Assumption 14
Failed to solve
⊢ Type 5 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type 5
Assumption 15
Failed to solve
⊢ Type M ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M
Assumption 16
Failed to solve
⊢ Type U ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U
Assumption 17
Failed to solve
⊢
(?M::1 ≈ Type M+1) ⊕ (?M::1 ≈ Type M+2) ⊕ (?M::1 ≈ Type M+3) ⊕ (?M::1 ≈ Type M) ⊕ (?M::1 ≈ Type U)
Destruct/Decompose
⊢ Type M+1 ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type M
Assumption 18
Failed to solve
⊢ Type M+1 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M+1
Assumption 19
Failed to solve
⊢ Type M+2 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M+2
Assumption 20
Failed to solve
⊢ Type M+3 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M+3
Assumption 21
Failed to solve
⊢ Type M ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M
Assumption 22
Failed to solve
⊢ Type U ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U
Assumption 23
Failed to solve
⊢
(?M::1 ≈ Type U+1) ⊕ (?M::1 ≈ Type U+2) ⊕ (?M::1 ≈ Type U+3) ⊕ (?M::1 ≈ Type M) ⊕ (?M::1 ≈ Type U)
Destruct/Decompose
⊢ Type U+1 ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type U
Assumption 24
Failed to solve
⊢ Type U+1 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U+1
Assumption 25
Failed to solve
⊢ Type U+2 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U+2
Assumption 26
Failed to solve
⊢ Type U+3 ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U+3
Assumption 27
Failed to solve
⊢ Type M ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type M
Assumption 28
Failed to solve
⊢ Type U ≺ Type
Substitution
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Assignment
⊢ ?M::1 ≈ Type U
Assumption 29
Failed to solve
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ a ≺ if (if a b ⊤) a ⊤
Substitution
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ a ≺ ?M::5[lift:0:1]
Substitution
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ ?M::8 ≺ ?M::5[lift:0:1]
Destruct/Decompose
a : Bool, b : Bool, H : ?M::2 ⊢ Π H_na : ?M::7, ?M::8 ≺ Π _ : ?M::4, ?M::5[lift:0:1]
(line: 27: pos: 21) Type of argument 6 must be convertible to the expected type in the application of
DisjCases::explicit
with arguments:
?M::3
?M::4
?M::5
EM a
λ H_a : ?M::6, H
λ H_na : ?M::7, NotImp1 (MT H H_na)
Assignment
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ a ≈ ?M::8
Destruct/Decompose
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ if a b ⊤ ≈ if ?M::8 ?M::9 ⊤
Normalize
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ if a b ⊤ ≈ ?M::8 ⇒ ?M::9
Substitution
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ if a b ⊤ ≈ ?M::10
Destruct/Decompose
a : Bool,
b : Bool,
H : ?M::2,
H_na : ?M::7 ⊢
if (if a b ⊤) a ⊤ ≺ if ?M::10 ?M::11 ⊤
Normalize
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ (a ⇒ b) ⇒ a ≺ if ?M::10 ?M::11 ⊤
Substitution
a : Bool,
b : Bool,
H : ?M::2,
H_na : ?M::7 ⊢
?M::2[lift:0:2] ≺ if ?M::10 ?M::11 ⊤
Normalize
a : Bool,
b : Bool,
H : ?M::2,
H_na : ?M::7 ⊢
?M::2[lift:0:2] ≺ ?M::10 ⇒ ?M::11
(line: 29: pos: 48) Type of argument 3 must be convertible to the expected type in the application of
MT::explicit
with arguments:
?M::10
?M::11
H
H_na
Normalize assignment
?M::0
Assignment
a : Bool, b : Bool ⊢ ?M::2 ≈ ?M::0
Destruct/Decompose
a : Bool,
b : Bool ⊢
Π H : ?M::2, ?M::5 ≺ Π _ : ?M::0, ?M::1[lift:0:1]
(line: 27: pos: 4) Type of argument 3 must be convertible to the expected type in the application of
Discharge::explicit
with arguments:
?M::0
?M::1
λ H : ?M::2,
DisjCases
(EM a)
(λ H_a : ?M::6, H)
(λ H_na : ?M::7, NotImp1 (MT H H_na))
Assignment
a : Bool, b : Bool ⊢ ?M::0 ≈ (a ⇒ b) ⇒ a
Destruct/Decompose
a : Bool, b : Bool ⊢ ?M::0 ⇒ ?M::1 ≺ ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
a : Bool ⊢
Π b : Bool, ?M::0 ⇒ ?M::1 ≺
Π b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
⊢
Π a b : Bool, ?M::0 ⇒ ?M::1 ≺
Π a b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
(line: 26: pos: 16) Type of definition 'pierce' must be convertible to expected type.
Assignment
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ ?M::10 ≈ ?M::8 ⇒ ?M::9
Destruct/Decompose
a : Bool, b : Bool, H : ?M::2, H_na : ?M::7 ⊢ ¬ ?M::10 ≺ ¬ (?M::8 ⇒ ?M::9)
(line: 29: pos: 40) Type of argument 3 must be convertible to the expected type in the application of
NotImp1::explicit
with arguments:
?M::8
?M::9
MT H H_na
Assignment
a : Bool, b : Bool, H : ?M::2 ⊢ if (if a b ⊤) a ⊤ ≺ ?M::5
Normalize
a : Bool, b : Bool, H : ?M::2 ⊢ (a ⇒ b) ⇒ a ≺ ?M::5
Normalize
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ (a ⇒ b) ⇒ a ≺ ?M::5[lift:0:1]
Substitution
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ ?M::2[lift:0:2] ≺ ?M::5[lift:0:1]
Destruct/Decompose
a : Bool,
b : Bool,
H : ?M::2 ⊢
Π H_a : ?M::6, ?M::2[lift:0:2] ≺ Π _ : ?M::3, ?M::5[lift:0:1]
(line: 27: pos: 21) Type of argument 5 must be convertible to the expected type in the application of
DisjCases::explicit
with arguments:
?M::3
?M::4
?M::5
EM a
λ H_a : ?M::6, H
λ H_na : ?M::7, NotImp1 (MT H H_na)
Normalize assignment
?M::0
Assignment
a : Bool, b : Bool ⊢ ?M::2 ≈ ?M::0
Destruct/Decompose
a : Bool, b : Bool ⊢ Π H : ?M::2, ?M::5 ≺ Π _ : ?M::0, ?M::1[lift:0:1]
(line: 27: pos: 4) Type of argument 3 must be convertible to the expected type in the application of
Discharge::explicit
with arguments:
?M::0
?M::1
λ H : ?M::2,
DisjCases (EM a) (λ H_a : ?M::6, H) (λ H_na : ?M::7, NotImp1 (MT H H_na))
Assignment
a : Bool, b : Bool ⊢ ?M::0 ≈ (a ⇒ b) ⇒ a
Destruct/Decompose
a : Bool, b : Bool ⊢ ?M::0 ⇒ ?M::1 ≺ ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
a : Bool ⊢ Π b : Bool, ?M::0 ⇒ ?M::1 ≺ Π b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
⊢ Π a b : Bool, ?M::0 ⇒ ?M::1 ≺ Π a b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
(line: 26: pos: 16) Type of definition 'pierce' must be convertible to expected type.
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