auto gitdoc commit

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Michael Zhang 2024-04-22 01:49:22 +00:00
parent 2e416a404f
commit dc32aadeb3

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@ -89,6 +89,8 @@ exercise2∙13 = aux1 , equiv1
-- known that (f ∘ g) x ≡ x
-- g (f x) ≡ x
-- g (f true) ≡ true
-- maybe a proof by contradiction? suppose f true ≡ f false. why doesn't this work if f ∘ g id?
-- how to work backwards from the f ∘ g id? since we have a value `g-id` of that
asdf true = {! !}
asdf false = {! !}