lecture 7

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#import "prooftree.typ": *
#import "@preview/showybox:2.0.1": showybox
#import "@preview/commute:0.2.0": node, arr, commutative-diagram
#import "@preview/cetz:0.2.2": *
#set page(width: 5.6in, height: 9in, margin: 0.4in)
#let isofhlevel = $sans("isofhlevel")$
#let PathOver = $sans("PathOver")$
#let ua = $sans("ua")$
#let idtoeqv = $sans("idtoeqv")$
#let Helix = $sans("Helix")$
#let UU = $cal(U)$
#let transport = $sans("transport")$
#let base = $sans("base")$
#let ap = $sans("ap")$
#let loop = $sans("loop")$
#let Circle = $bb(S)^1$
#let idtoiso = $sans("idtoiso")$
#let Nat = $sans("Nat")$
#let Vect = $sans("Vect")$
#let Bool = $sans("Bool")$
#let carrier = $sans("carrier")$
#let iseqclass = $sans("iseqclass")$
#let isInjective = $sans("isInjective")$
#let Type = $sans("Type")$
#let reflexive = $sans("reflexive")$
#let Even = $sans("Even")$
#let isEven = $sans("isEven")$
#let Prop = $sans("Prop")$
#let isProp = $sans("isProp")$
#let Set = $sans("Set")$
#let isContr = $sans("isContr")$
#let isIso = $sans("isIso")$
#let isEquiv = $sans("isEquiv")$
#let isSet = $sans("isSet")$
#let zero = $sans("zero")$
#let suc = $sans("suc")$
#let Monoid = $sans("Monoid")$
#let MonoidStr = $sans("MonoidStr")$
#let MonoidAxioms = $sans("MonoidAxioms")$
#let refl = $sans("refl")$
#let defeq = $equiv$
#let propeq = $=$
= Synthetic Homotopy Theory
We are talking about _the_ circle today!
What do all these words mean?
- #[
*Homotopy theory.* Study of topological spaces up to continuous deformation. You might have heard we don't distinguish coffee cup and donuts. But it's getting worse.
We don't distinguish bagels and rubber bands, even if the rubber band doesn't have any thickness. Topologists distinguish them, but we don't. If you cut a hole in a piece of paper, that's still a bagel.
They collapse many of the differences. The technical term is _continuous deformation_. As long as nothing is being torn apart, that's ok. (don't eat the bagel)
]
- #[
*Synthetic.* There's a coordinate system, and you can get the location of any objects in the system. You can just solve equations via algebra on the coordinate system instead. This is called the _analytic_ way of thinking. We are *not* doing that.
Instead, we are going back to the Euclidean geometry. "There's a line between two points" doesn't specify what the line actually is. This is called _synthetic_, since it's just based on the axioms.
]
=== Example
The standard circle of size 1 is typically defined (_analytically_) as $ {(x, y) | x^2 + y^2 = 1} $
We are not doing this. Instead, we are defining the circle as the combination of
- a point $base$
- some abstract $loop$ from $base$ to itself
We don't necessarily know what it looks like, or know how it works. This is a _synthetic_ approach.
#align(center)[#line(length: 4cm)]
One question is: this picture looks reasonable, but how do we do this in type theory? The type theory doesn't provide a reasonable way to talk about the $loop$. But we can talk about paths in the type, so we can represent $loop$ as a path.
=== Definition using Coq notation
```
Inductive Circle : U :=
| base : Circle
| loop : base ≡ base.
```
The $loop$ is a path constructor, which is not supported by Coq. How do we eliminate this circle (how do I define a function that uses a circle)?
Mimicking the Coq notation again, we would have:
```
match (x : Circle) with
| base => ...
| loop => ...
end
```
What should we do with the second case? This is already kind of suspicious since it doesn't have type $Circle$. Also, what should be the output obligation?
Suppose we define a function $f : Circle -> A$. We probably want the $base$ point to be sent somewhere such that $f(base) : A$.
Intuitively, there should also be a loop in $A$, that is a path, that is "$f(loop)$". The path should be $f(base) propeq f(base)$. We put quotes around "$f(loop)$" because $f(loop)$ doesn't actually type-check in the theory. What we need right now is the map on paths $ap_f (loop)$.
=== Dependent cases
If $A$ depends on the circle, we can take a fibrational view. Imagine there are many fibers over the circle on the ground. In this case, $f(base) : A(base)$. Then "$f(loop)$" is a line travelling through the collection of fibers that goes back to $base$. However, $ap_f (loop)$ doesn't travel through the fibers, which we need.
How can we specify something that is crossing different fibers? Suppose there are a collection of fibers $B : A -> U$ and a path $p : x propeq_A y$. There are endpoints $b_x : B(x)$ and $b_y : B(y)$ that travels through the collection of fibers. There are several ways to define this.
*Definition (path over).*
$ PathOver(p, b_x, b_y) :defeq (transport^B (p, b_x) propeq b_y) $
This is a path _in_ $B(y)$ between the transported $b_x$, which does the travelling between fibers.
```
match (x : Circle) with
| base => (fb : B base)
| loop => (... : PathOver loop fb fb)
```
=== Other examples of HITs
List of things to ask ChatGPT:
+ Spheres in arbitrary dimensions (circle is dimension 1)
+ Suspension
+ Arbitrary dimension of truncation
+ Homotopy pushouts
=== Algebraic topology
Why the word "algebraic"? Algebraic means you want to find some algebraic _invariants_ under continuous deformation. "If I'm allowing myself to equate bagels and rubber bands, what are the essential properties that are still the same?" For example, the bagel has a hole, and the rubber band also has a hole in it. We can turn this into a number we can calculate.
Why do we care about this property? How can we prove that a bagel is different from a solid ball? If you can prove that the number of holes is an invariant on the deformation process, then it's a good way to classify different objects.
One important thing is called the *fundamental group*.
=== Fundamental group
Fundamental group only works when u have an element in the type. Suppose a space $X$ with a point $x_0 : X$. We can define a _group_ on the paths.
$ { "paths" x_0 propeq x_0 } \/ "homotopy" $
You can prove it satisfies all the group laws (refl, concatenation, inverse). We will reproduce this in type theory.
#let trunc(x) = $bar.double #x bar.double$
*Definition (fundamental group).* $ pi_1 (X, x_0) &:defeq trunc(x_0 propeq x_0)_0 \
&:defeq trunc(Omega(X, x_0))_0 $
We need the $x_0 propeq x_0$ to be a set, since it may have some higher structure.
*Definition (loop space).* Loop space does not forget the interesting higher dimensional structures.
$ Omega(X, x_0) :defeq (x_0 propeq x_0) $
Now we can state the theorem.
*Theorem.* $pi_1 (Circle, base) tilde.eq ZZ$.
*Theorem.* $Omega(Circle, base) tilde.eq ZZ$.
Quick proof sketch: expanding the definition, we are trying to prove: $base propeq base tilde.eq ZZ$.
What do we need for equivalence? Function going right, function going left, and prove that there are inverses going both directions. Consider the easy case: $g : ZZ -> base propeq base$
- $g(-1) = loop^(-1)$
- $g(0) = refl$
- $g(1) = loop$
- $g(2) = loop dot loop$
Intuitively, this represents "how many times are you going around the circle"? With the opposite direction being the negative numbers. There is a name for this, called *winding numbers*.
The other direction $f : (p : base propeq base) -> ZZ$ is more complicated. We can't really do induction on the loop like the integers. The trick is to construct a *covering space*. In the case of the circle, this looks like a helix going up.
The fiber of $base$ is $Z$. Then, you can follow the unknown path $p$ around the circle and simultaneously wind up and down the circular stairs.
#image("winding.jpeg", height: 3in)
+ We want to build a helix.
+ Transport zero along the path $p$
+ The final number is the output, the *winding number*
Define: $Helix : Circle -> UU$ (non-dependent case, so slightly easier)
- $Helix(base) :defeq ZZ$
We can define the result of the path $ZZ propeq ZZ$. But due to univalence, we can use an equivalence here instead.
The successor function is a good equivalence to give us this winding functionality.
- $Helix(loop) :defeq ua(suc) : ZZ propeq ZZ$
Now, we can define $f$:
$ f :defeq lambda p. transport^Helix (p, 0) $
Then, prove that $f$ and $g$ are inverses of each other, and then you would prove that $base propeq base tilde.eq ZZ$.

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