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- https://mzhang.io
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2020-07-21
Path between fibers for boolean equivalence
ok going to try this again without cubical in this doc
using path induction, I was able…
Exercise 2.4: n-dimensional path
Just putting some old attempts here:
-- data nPath {A : Type} : ℕ → Type where
-- zeroPath : (x y : A) → (p : x ≡ y) → nPath zero …
Port cohomology paper to cubical Agda
Write a blog post for the fundamental group of a circle ≡ integers
Path between fibers for boolean equivalence
Trying this again in this file
I feel like the answer here was I'm trying to make fx and fz ≡…
Incorporate reverse-ap for proving equivalence
I think I got the idea, see this file
eqv5 : convert-inv (convert z) ≡ convert-inv (convert…
Incorporate reverse-ap for proving equivalence
Bi-invertible equivalence
I think this is resolved in 9716b4b69b3af70dcab68ed3d5321adb8789dfbd ?
reason for i think is because the Iso
doesn't actually use the BiInvEquiv
itself, but i think that's fine for now