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Typo fix (issue #15)
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@ -3625,7 +3625,7 @@ Formally, we define $\pors{h, l, \concat{(c, s)}{S}}$ as follows, recalling that
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\begin{itemize}
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\item There is some $c_0$ where $\na{c} = c_0$. That is, thread $c$ has some atomic action lined up to run next.
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\item There exist $h'$, $l'$, and $c'$ such that $\smallstep{(h, l, c)}{(h', l', c')}$. That is, thread $c$ is actually able to take a step, which might not be possible if e.g. trying to take a lock that is already held.
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\item For every $(c_1, s) \in S$, we have $\commu{c_0}{c_1}$. That is, all actions that other threads might perform commute with $c_0$, the first action of $c$.
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\item For every $(c_1, s) \in S$, we have $\commu{c_0}{s}$. That is, all actions that other threads might perform commute with $c_0$, the first action of $c$.
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\end{itemize}
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\newcommand{\smallstepC}[2]{#1 \to_C #2}
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