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Typo fix
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@ -1302,7 +1302,7 @@ That is, when $p \in \Gamma$, we have $v(p) = \top$; and when $\neg p \in \Gamma
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Given context $\Gamma$ and formula $\phi$, if
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\begin{itemize}
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\item there is no variable $p$ such that both $p \in \Gamma$ and $\neg p \in \Gamma$, and
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\item for any valuation $v$ compatible with $\Gamma$, we have $\denote{p}v$,
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\item for any valuation $v$ compatible with $\Gamma$, we have $\denote{\phi}v$,
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\end{itemize}
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then $\Gamma \vdash \phi$.
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\end{lemma}
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