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Finished LambdaCalculus chapter
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@ -546,7 +546,7 @@ Module Stlc.
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(* That language is suitable to describe with a static *type system*. Here's
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* our modest, but countably infinite, set of types. *)
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Inductive type : Set :=
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Inductive type :=
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| Nat (* Numbers *)
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| Fun (dom ran : type) (* Functions *).
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@ -19,3 +19,4 @@ ModelChecking.v
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OperationalSemantics_template.v
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OperationalSemantics.v
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AbstractInterpretation.v
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LambdaCalculusAndTypeSoundness.v
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137
frap_book.tex
137
frap_book.tex
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@ -2040,7 +2040,7 @@ $$\begin{array}{rrcl}
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\textrm{Expressions} & e &::=& x \mid \lambda x. \; e \mid e \; e
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\end{array}$$
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An expression $\lambda x. \; e$\index{$\lambda$ expression} is a first-class, anonymous function, also called a \emph{function abstraction}\index{function abstraction}.
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An expression $\lambda x. \; e$\index{$\lambda$ expression} is a first-class, anonymous function, also called a \emph{function abstraction}\index{function abstraction} or \emph{$\lambda$-abstraction}\index{$\lambda$-abstraction}.
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When called, it replaces its formal-argument variable $x$ with the actual argument within $e$ and continues evaluating.
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The third syntactic form $e \; e$ uses \emph{juxtaposition}\index{juxtaposition}, or writing one term after another, for function application.
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@ -2216,6 +2216,141 @@ We define $\mathbb T(e) = \angled{\mathcal L, \{e\}, \to}$.
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The next section gives probably the most celebrated $\lambda$-calculus result based on the transition-system perspective.
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\section{Simple Types and Their Soundness}
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Let's spruce up the language with some more constructs.
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$$\begin{array}{rrcl}
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\textrm{Variables} & x &\in& \mathsf{Strings} \\
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\textrm{Numbers} & n &\in& \mathbb N \\
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\textrm{Expressions} & e &::=& n \mid e + e \mid x \mid \lambda x. \; e \mid e \; e \\
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\textrm{Values} & v &::=& n \mid \lambda x. \; e
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\end{array}$$
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We've added natural numbers as a primitive feature, supported via constants and addition.
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Numbers may be intermixed with functions, and we may, for instance, write first-class functions that take numbers as input or return numbers.
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Our language of evaluation contexts expands a bit.
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$$\begin{array}{rrcl}
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\textrm{Evaluation contexts} & C &::=& \Box \mid C \; e \mid v \; C \mid C + e \mid v + C
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\end{array}$$
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Now we want to define two kinds of basic small steps, so it is worth defining a separate relation for them.
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Here we face a classic nuisance in writing rules that combine explicit syntax with standard mathematical operators, and we write $+$ for the syntactic construct and $\textbf{+}$ for the mathematical addition operator.
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$$\infer{\smallstepo{(\lambda x. \; e) \; v}{\subst{e}{x}{v}}}{}
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\quad \infer{\smallstepo{n + m}{n \textbf{+} m}}{}$$
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Here is the overall step rule.
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$$\infer{\smallstep{\plug{C}{e}}{\plug{C}{e'}}}{
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\smallstepo{e}{e'}
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}$$
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What would be a useful property to prove about our new expressions?
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For one thing, we don't want them to ``crash,'' as in the expression $(\lambda x. \; x) + 7$ that tries to add a function and a number.
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No rule of the semantics knows what to do with that case, but it also isn't a value, so we shouldn't consider it as finished with evaluation.
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Define an expression as \emph{stuck}\index{stuck term} when it is not a value and it cannot take a small step.
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For ``reasonable'' expressions $e$, we should be able to prove that it is an invariant of $\mathbb T(e)$ that no expression is ever stuck.
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To define ``reasonable,'' we formalize the popular idea of a static type system.
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Every expression will be assigned a type, capturing which sorts of contexts it may legally be dropped into.
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Our language of types is simple.
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\abstraction
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$$\begin{array}{rrcl}
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\textrm{Types} & \tau &::=& \mathbb N \mid \tau \to \tau
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\end{array}$$
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We have trees of function-space constructors, where all the leaves are instances of the natural-number type $\mathbb N$.
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Note that, with type assignment, we have yet another case of \emph{abstraction}, approximating a potentially complex expression with a type that only records enough information to rule out crashes.
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\newcommand{\hasty}[3]{#1 \vdash #2 : #3}
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To assign types to closed terms, we must recursively define what it means for an open term to have a type.
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To that end, we use \emph{typing contexts}\index{typing context} $\Gamma$, finite maps from variables to types.
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To mimic standard notation, we write $\Gamma, x : \tau$ as shorthand for $\mupd{\Gamma}{x}{\tau}$, overriding of key $x$ with value $\tau$ in $\Gamma$.
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Now we define typing as a three-place relation, written $\hasty{\Gamma}{e}{\tau}$, to indicate that, assuming $\Gamma$ as an assignment of types to $e$'s free variables, we conclude that $e$ has type $\tau$.
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We define the relation inductively, with one case per syntactic construct.
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\modularity
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$$\infer{\hasty{\Gamma}{x}{\tau}}{
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\msel{\Gamma}{x} = \tau
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}
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\quad \infer{\hasty{\Gamma}{n}{\mathbb N}}{}
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\quad \infer{\hasty{\Gamma}{e_1 + e_2}{\mathbb N}}{
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\hasty{\Gamma}{e_1}{\mathbb N}
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& \hasty{\Gamma}{e_2}{\mathbb N}
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}$$
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$$\infer{\hasty{\Gamma}{\lambda x. \; e}{\tau_1 \to \tau_2}}{
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\hasty{\Gamma, x : \tau_1}{e}{\tau_2}
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}
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\quad \infer{\hasty{\Gamma}{e_1 \; e_2}{\tau_2}}{
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\hasty{\Gamma}{e_1}{\tau_1 \to \tau_2}
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& \hasty{\Gamma}{e_2}{\tau_1}
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}$$
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We write $\hasty{}{e}{\tau}$ as shorthand for $\hasty{\mempty}{e}{\tau}$, meaning that closed term $e$ has type $\tau$, with no typing context required.
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Note that this style of typing rules provides another instance of \emph{modularity}, since we can separately type-check different subexpressions of a large expression, using just their types to coordinate expectations among subexpressions.
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It should be an invariant of $\mathbb T(e)$ that every reachable expression has the same type as the original, so long as the original was well-typed.
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This observation is the key to proving that it is also an invariant that no reachable expression is stuck, using a proof technique called \emph{the syntactic approach to type soundness}\index{syntactic approach to type soundness}, which turns out to be just another instance of our general toolbox for invariant proofs.
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We work our way through a suite of standard lemmas to support that invariant proof.
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\begin{lemma}[Progress]\label{progress}
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If $\hasty{}{e}{\tau}$, then $e$ isn't stuck.
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\end{lemma}
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\begin{proof}
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By induction on the derivation of $\hasty{}{e}{\tau}$.
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\end{proof}
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\begin{lemma}[Weakening]\label{weakening}
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If $\hasty{\Gamma}{e}{\tau}$ and every mapping in $\Gamma$ is also included in $\Gamma'$, then $\hasty{\Gamma'}{e}{\tau}$.
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\end{lemma}
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\begin{proof}
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By induction on the derivation of $\hasty{\Gamma}{e}{\tau}$.
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\end{proof}
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\begin{lemma}[Substitution]\label{substitution}
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If $\hasty{\Gamma, x : \tau'}{e}{\tau}$ and $\hasty{}{e'}{\tau'}$, then $\hasty{\Gamma}{\subst{e}{x}{e'}}{\tau}$.
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\end{lemma}
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\begin{proof}
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By induction on the derivation of $\hasty{\Gamma, x: \tau'}{e}{\tau}$, with appeal to Lemma \ref{weakening}.
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\end{proof}
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\begin{lemma}\label{preservation0}
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If $\smallstepo{e}{e'}$ and $\hasty{}{e}{\tau}$, then $\hasty{}{e'}{\tau}$.
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\end{lemma}
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\begin{proof}
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By inversion on the derivation of $\smallstepo{e}{e'}$, with appeal to Lemma \ref{substitution}.
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\end{proof}
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\begin{lemma}\label{generalize_plug}
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If any type of $e_1$ is also a type of $e_2$, then any type of $\plug{C}{e_1}$ is also a type of $\plug{C}{e_2}$.
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\end{lemma}
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\begin{proof}
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By induction on the structure of $C$.
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\end{proof}
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\begin{lemma}[Preservation]\label{preservation}
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If $\smallstep{e_1}{e_2}$ and $\hasty{}{e_1}{\tau}$, then $\hasty{}{e_2}{\tau}$.
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\end{lemma}
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\begin{proof}
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By inversion on the derivation of $\smallstep{e_1}{e_2}$, with appeal to Lemmas \ref{preservation0} and \ref{generalize_plug}.
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\end{proof}
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\invariants
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\begin{theorem}[Type Soundness]
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If $\hasty{}{e}{\tau}$, then $\neg \textrm{stuck}$ is an invariant of $\mathbb T(e)$.
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\end{theorem}
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\begin{proof}
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First, we strengthen the invariant to $I(e) = \; \hasty{}{e}{\tau}$, justifying the implication by Lemma \ref{progress}, Progress.
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Then we apply invariant induction, where the base case is trivial.
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The induction step is a direct match for Lemma \ref{preservation}, Preservation.
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\end{proof}
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The syntactic approach to type soundness is often presented as a proof technique in isolation, but what we see here is that it follows very directly from our general invariant proof technique.
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Usually syntactic type soundness is presented as fundamentally about proving Progress and Preservation conditions.
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The Progress condition maps to invariant strengthening, and the Preservation condition maps to invariant induction, which we have used in almost every invariant proof so far.
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Since the basic proof structure matches our standard one, the main insight is the usual one: a good choice of a strengthened invariant.
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In this case, invariant $I(e) = \; \hasty{}{e}{\tau}$ is that crucial insight, including the original design of the set of types and the typing relation.
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%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
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\appendix
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