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875 lines
22 KiB
Coq
875 lines
22 KiB
Coq
(** Formal Reasoning About Programs <http://adam.chlipala.net/frap/>
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* Chapter 11: Lambda Calculus and Simple Type Soundness
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* Author: Adam Chlipala
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* License: https://creativecommons.org/licenses/by-nc-nd/4.0/ *)
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Require Import Frap.
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(* The last few chapters have focused on small programming languages that are
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* representative of the essence of the imperative languages. We now turn to
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* lambda-calculus, the usual representative of functional languages. *)
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Module Ulc.
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(* Programs are expressions, which we evaluate algebraically, rather than
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* executing for side effects. *)
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Inductive exp : Set :=
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| Var (x : var)
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| Abs (x : var) (body : exp)
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(* A function that binds its argument to the given variable, evaluating the
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* body expression *)
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| App (e1 e2 : exp).
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(* Applying a function to an argument *)
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(* Key operation: within [e], changing every occurrence of variable [x] into
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* [rep]. IMPORTANT: we will only apply this operation in contexts where
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* [rep] is *closed*, meaning every [Var] refers to some enclosing [Abs], so
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* as to avoid *variable capture*. See the book proper for a little more
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* discussion. *)
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Fixpoint subst (rep : exp) (x : var) (e : exp) : exp :=
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match e with
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| Var y => if y ==v x then rep else Var y
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| Abs y e1 => Abs y (if y ==v x then e1 else subst rep x e1)
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| App e1 e2 => App (subst rep x e1) (subst rep x e2)
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end.
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(** * Big-step semantics *)
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(* This is the most straightforward way to give semantics to lambda terms:
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* We evaluate any closed term into a value (that is, an [Abs]). *)
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Inductive eval : exp -> exp -> Prop :=
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| BigAbs : forall x e,
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eval (Abs x e) (Abs x e)
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| BigApp : forall e1 x e1' e2 v2 v,
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eval e1 (Abs x e1')
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-> eval e2 v2
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-> eval (subst v2 x e1') v
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-> eval (App e1 e2) v.
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(* Note that we omit a [Var] case, since variable terms can't be *closed*,
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* and therefore they aren't meaningful as top-level programs. *)
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(* Which terms are values, that is, final results of execution? *)
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Inductive value : exp -> Prop :=
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| Value : forall x e, value (Abs x e).
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(* We're cheating a bit here, *assuming* that the term is also closed. *)
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Local Hint Constructors eval value : core.
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(* Every value executes to itself. *)
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Theorem value_eval : forall v,
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value v
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-> eval v v.
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Proof.
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invert 1; eauto.
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Qed.
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Local Hint Resolve value_eval : core.
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(* Conversely, let's prove that [eval] only produces values. *)
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Theorem eval_value : forall e v,
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eval e v
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-> value v.
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Proof.
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induct 1; eauto.
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Qed.
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Local Hint Resolve eval_value : core.
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(* Some notations, to let us write more normal-looking lambda terms *)
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Coercion Var : var >-> exp.
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Notation "\ x , e" := (Abs x e) (at level 50).
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Infix "@" := App (at level 49, left associativity).
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(* Believe it or not, this is a Turing-complete language! Here's an example
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* nonterminating program. *)
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Example omega := (\"x", "x" @ "x") @ (\"x", "x" @ "x").
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Theorem omega_no_eval : forall v, eval omega v -> False.
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Proof.
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induct 1.
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invert H.
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invert H0.
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simplify.
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apply IHeval3.
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trivial.
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Qed.
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(** * Church Numerals, everyone's favorite example of lambda terms in
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* action *)
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(* Here are two curious definitions. *)
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Definition zero := \"f", \"x", "x".
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Definition plus1 := \"n", \"f", \"x", "f" @ ("n" @ "f" @ "x").
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(* We can build up any natural number [n] as [plus1^n @ zero]. Let's prove
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* that, in fact, these definitions constitute a workable embedding of the
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* natural numbers in lambda-calculus. *)
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(* A term [plus^n @ zero] evaluates to something very close to what this
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* function returns. *)
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Fixpoint canonical' (n : nat) : exp :=
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match n with
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| O => "x"
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| S n' => "f" @ ((\"f", \"x", canonical' n') @ "f" @ "x")
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end.
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(* This missing piece is this wrapper. *)
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Definition canonical n := \"f", \"x", canonical' n.
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(* Let's formalize our definition of what it means to represent a number. *)
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Definition represents (e : exp) (n : nat) :=
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eval e (canonical n).
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(* Zero passes the test. *)
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Theorem zero_ok : represents zero 0.
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Proof.
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unfold zero, represents, canonical.
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simplify.
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econstructor.
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Qed.
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(* So does our successor operation. *)
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Theorem plus1_ok : forall e n, represents e n
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-> represents (plus1 @ e) (S n).
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Proof.
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unfold plus1, represents, canonical; simplify.
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econstructor.
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econstructor.
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eassumption.
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simplify.
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econstructor.
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Qed.
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(* What's basically going on here? The representation of number [n] is [N]
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* such that, for any function [f]:
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* N(f) = f^n
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* That is, we represent a number as its repeated-composition operator.
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* So, given a number, we can use it to repeat any operation. In particular,
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* to implement addition, we can just repeat [plus1]! *)
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Definition add := \"n", \"m", "n" @ plus1 @ "m".
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(* Our addition works properly on this test case. *)
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Example add_1_2 : exists v,
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eval (add @ (plus1 @ zero) @ (plus1 @ (plus1 @ zero))) v
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/\ eval (plus1 @ (plus1 @ (plus1 @ zero))) v.
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Proof.
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eexists; propositional.
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repeat (econstructor; simplify).
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repeat econstructor.
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Qed.
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(* By the way: since [canonical'] doesn't mention variable "m", substituting
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* for "m" has no effect. This fact will come in handy shortly. *)
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Lemma subst_m_canonical' : forall m n,
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subst m "m" (canonical' n) = canonical' n.
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Proof.
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induct n; simplify; equality.
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Qed.
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(* This inductive proof is the workhorse for the next result, so let's skip
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* ahead there. *)
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Lemma add_ok' : forall m n,
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eval
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(subst (\ "f", (\ "x", canonical' m)) "x"
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(subst (\ "n", (\ "f", (\ "x", "f" @ (("n" @ "f") @ "x")))) "f"
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(canonical' n))) (canonical (n + m)).
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Proof.
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induct n; simplify.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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simplify.
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econstructor.
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econstructor.
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simplify.
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eassumption.
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simplify.
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econstructor.
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Qed.
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(* [add] properly encodes the usual addition. *)
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Theorem add_ok : forall n ne m me,
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represents ne n
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-> represents me m
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-> represents (add @ ne @ me) (n + m).
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Proof.
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unfold represents; simplify.
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econstructor.
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econstructor.
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econstructor.
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eassumption.
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simplify.
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econstructor.
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eassumption.
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simplify.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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simplify.
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econstructor.
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econstructor.
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rewrite subst_m_canonical'.
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apply add_ok'.
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Qed.
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(* Let's repeat the same exercise for multiplication. *)
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Definition mult := \"n", \"m", "n" @ (add @ "m") @ zero.
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Example mult_1_2 : exists v,
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eval (mult @ (plus1 @ zero) @ (plus1 @ (plus1 @ zero))) v
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/\ eval (plus1 @ (plus1 @ zero)) v.
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Proof.
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eexists; propositional.
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repeat (econstructor; simplify).
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repeat econstructor.
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Qed.
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Lemma mult_ok' : forall m n,
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eval
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(subst (\ "f", (\ "x", "x")) "x"
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(subst
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(\ "m",
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((\ "f", (\ "x", canonical' m)) @
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(\ "n", (\ "f", (\ "x", "f" @ (("n" @ "f") @ "x"))))) @ "m")
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"f" (canonical' n))) (canonical (n * m)).
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Proof.
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induct n; simplify.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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simplify.
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econstructor.
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econstructor.
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simplify.
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eassumption.
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simplify.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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simplify.
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econstructor.
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econstructor.
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rewrite subst_m_canonical'.
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apply add_ok'. (* Note the recursive appeal to correctness of [add]. *)
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Qed.
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Theorem mult_ok : forall n ne m me,
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represents ne n
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-> represents me m
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-> represents (mult @ ne @ me) (n * m).
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Proof.
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unfold represents; simplify.
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econstructor.
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econstructor.
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econstructor.
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eassumption.
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simplify.
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econstructor.
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eassumption.
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simplify.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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econstructor.
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simplify.
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econstructor.
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simplify.
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econstructor.
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econstructor.
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simplify.
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rewrite subst_m_canonical'.
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apply mult_ok'.
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Qed.
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(** * Small-step semantics *)
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(* We can also port to this setting our small-step semantics style. *)
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(* Function application (called "beta reduction") is the big rule here. *)
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Inductive step : exp -> exp -> Prop :=
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| Beta : forall x e v,
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value v
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-> step (App (Abs x e) v) (subst v x e)
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(* However, we also need bureaucractic rules for pushing evaluation inside
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* applications. *)
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| App1 : forall e1 e1' e2,
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step e1 e1'
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-> step (App e1 e2) (App e1' e2)
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| App2 : forall v e2 e2',
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value v
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-> step e2 e2'
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-> step (App v e2) (App v e2').
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(* Note how that last rule enforces a deterministic evaluation order!
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* We call it *call-by-value*. *)
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Local Hint Constructors step : core.
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(* Here we now go through a proof of equivalence between big- and small-step
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* semantics, though we won't spend any further commentary on it. *)
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Lemma step_eval' : forall e1 e2,
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step e1 e2
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-> forall v, eval e2 v
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-> eval e1 v.
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Proof.
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induct 1; simplify; eauto.
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invert H0.
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econstructor.
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apply IHstep.
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eassumption.
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eassumption.
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assumption.
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invert H1.
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econstructor.
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eassumption.
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apply IHstep.
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eassumption.
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assumption.
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Qed.
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Local Hint Resolve step_eval' : core.
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Theorem step_eval : forall e v,
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step^* e v
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-> value v
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-> eval e v.
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Proof.
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induct 1; eauto.
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Qed.
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Local Hint Resolve eval_value : core.
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Theorem step_app1 : forall e1 e1' e2,
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step^* e1 e1'
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-> step^* (App e1 e2) (App e1' e2).
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Proof.
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induct 1; eauto.
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Qed.
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Theorem step_app2 : forall e2 e2' v,
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value v
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-> step^* e2 e2'
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-> step^* (App v e2) (App v e2').
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Proof.
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induct 2; eauto.
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Qed.
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Theorem eval_step : forall e v,
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eval e v
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-> step^* e v.
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Proof.
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induct 1; eauto.
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eapply trc_trans.
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apply step_app1.
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eassumption.
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eapply trc_trans.
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eapply step_app2.
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constructor.
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eassumption.
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econstructor.
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constructor.
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eauto.
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assumption.
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Qed.
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End Ulc.
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(** * Now we turn to a variant of lambda calculus with static type-checking.
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* This variant is called *simply typed* lambda calculus, and *simple* has a
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* technical meaning, basically meaning "no polymorphism" in the sense of
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* example file Polymorphism.v from this book. *)
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Module Stlc.
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(* We add expression forms for numeric constants and addition. *)
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Inductive exp : Set :=
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| Var (x : var)
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| Const (n : nat)
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| Plus (e1 e2 : exp)
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| Abs (x : var) (e1 : exp)
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| App (e1 e2 : exp).
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(* Values (final results of evaluation) *)
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Inductive value : exp -> Prop :=
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| VConst : forall n, value (Const n)
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| VAbs : forall x e1, value (Abs x e1).
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(* Substitution (not applicable when [e1] isn't closed, to avoid some complexity
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* that we don't need) *)
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Fixpoint subst (e1 : exp) (x : string) (e2 : exp) : exp :=
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match e2 with
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| Var y => if y ==v x then e1 else Var y
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| Const n => Const n
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| Plus e2' e2'' => Plus (subst e1 x e2') (subst e1 x e2'')
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| Abs y e2' => Abs y (if y ==v x then e2' else subst e1 x e2')
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| App e2' e2'' => App (subst e1 x e2') (subst e1 x e2'')
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end.
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(* Small-step, call-by-value evaluation *)
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Inductive step : exp -> exp -> Prop :=
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(* These rules show the real action of the semantics. *)
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| Beta : forall x e v,
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value v
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-> step (App (Abs x e) v) (subst v x e)
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| Add : forall n1 n2,
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step (Plus (Const n1) (Const n2)) (Const (n1 + n2))
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(* Then we have a bunch of bureaucratic, repetitive rules encoding evaluation
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* order. See next lecture for how to streamline this part, but for now note
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* that the [value] premises below are crucial to enforce a single order of
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* evaluation. *)
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| App1 : forall e1 e1' e2,
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step e1 e1'
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-> step (App e1 e2) (App e1' e2)
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| App2 : forall v e2 e2',
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value v
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-> step e2 e2'
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-> step (App v e2) (App v e2')
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| Plus1 : forall e1 e1' e2,
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step e1 e1'
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-> step (Plus e1 e2) (Plus e1' e2)
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| Plus2 : forall v e2 e2',
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value v
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-> step e2 e2'
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-> step (Plus v e2) (Plus v e2').
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(* It's easy to wrap everything as a transition system. *)
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Definition trsys_of (e : exp) := {|
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Initial := {e};
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Step := step
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|}.
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(* That language is suitable to describe with a static *type system*. Here's
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* our modest, but countably infinite, set of types. *)
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Inductive type :=
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| Nat (* Numbers *)
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| Fun (dom ran : type) (* Functions *).
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(* Our typing relation (also often called a "judgment") uses *typing contexts*
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* (not to be confused with evaluation contexts) to map free variables to
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* their types. Free variables are those that don't refer to enclosing [Abs]
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* binders. *)
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Inductive has_ty : fmap var type -> exp -> type -> Prop :=
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| HtVar : forall G x t,
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G $? x = Some t
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-> has_ty G (Var x) t
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| HtConst : forall G n,
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has_ty G (Const n) Nat
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| HtPlus : forall G e1 e2,
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has_ty G e1 Nat
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-> has_ty G e2 Nat
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-> has_ty G (Plus e1 e2) Nat
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| HtAbs : forall G x e1 t1 t2,
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has_ty (G $+ (x, t1)) e1 t2
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-> has_ty G (Abs x e1) (Fun t1 t2)
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| HtApp : forall G e1 e2 t1 t2,
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has_ty G e1 (Fun t1 t2)
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-> has_ty G e2 t1
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-> has_ty G (App e1 e2) t2.
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Local Hint Constructors value step has_ty : core.
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(* Some notation to make it more pleasant to write programs *)
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Infix "-->" := Fun (at level 60, right associativity).
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Coercion Const : nat >-> exp.
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Infix "^+^" := Plus (at level 50).
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Coercion Var : var >-> exp.
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Notation "\ x , e" := (Abs x e) (at level 51).
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Infix "@" := App (at level 49, left associativity).
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(* Some examples of typed programs *)
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Example one_plus_one : has_ty $0 (1 ^+^ 1) Nat.
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Proof.
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repeat (econstructor; simplify).
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Qed.
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Example add : has_ty $0 (\"n", \"m", "n" ^+^ "m") (Nat --> Nat --> Nat).
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Proof.
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repeat (econstructor; simplify).
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Qed.
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Example eleven : has_ty $0 ((\"n", \"m", "n" ^+^ "m") @ 7 @ 4) Nat.
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Proof.
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repeat (econstructor; simplify).
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Qed.
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Example seven_the_long_way : has_ty $0 ((\"x", "x") @ (\"x", "x") @ 7) Nat.
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Proof.
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repeat (econstructor; simplify).
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Qed.
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(** * Let's prove type soundness first without much automation. *)
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(* What useful invariants could we prove about programs in this language? How
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* about that, at every point, either they're finished executing or they can
|
|
* take further steps? For instance, a program that tried to add a function
|
|
* to a number would not satisfy that condition, and we call it *stuck*. We
|
|
* want to prove that typed programs can never become stuck. Here's a good
|
|
* invariant to strive for. *)
|
|
Definition unstuck e := value e
|
|
\/ (exists e' : exp, step e e').
|
|
|
|
(* Now we're ready for the first of the two key properties to establish that
|
|
* invariant: well-typed programs are never stuck. *)
|
|
Lemma progress : forall e t,
|
|
has_ty $0 e t
|
|
-> unstuck e.
|
|
Proof.
|
|
unfold unstuck; induct 1; simplify; try equality.
|
|
|
|
left.
|
|
constructor.
|
|
|
|
propositional.
|
|
|
|
right.
|
|
(* Some automation is needed here to maintain compatibility with
|
|
* name generation in different Coq versions. *)
|
|
match goal with
|
|
| [ H1 : value e1, H2 : has_ty $0 e1 _ |- _ ] => invert H1; invert H2
|
|
end.
|
|
match goal with
|
|
| [ H1 : value e2, H2 : has_ty $0 e2 _ |- _ ] => invert H1; invert H2
|
|
end.
|
|
exists (Const (n + n0)).
|
|
constructor.
|
|
|
|
match goal with
|
|
| [ H : exists x, _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (x ^+^ e2).
|
|
constructor.
|
|
assumption.
|
|
|
|
match goal with
|
|
| [ H : exists x, _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (e1 ^+^ x).
|
|
apply Plus2.
|
|
assumption.
|
|
assumption.
|
|
|
|
match goal with
|
|
| [ H : exists x, _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (x ^+^ e2).
|
|
constructor.
|
|
assumption.
|
|
|
|
left.
|
|
constructor.
|
|
|
|
propositional.
|
|
|
|
right.
|
|
match goal with
|
|
| [ H1 : value e1, H2 : has_ty $0 e1 _ |- _ ] => invert H1; invert H2
|
|
end.
|
|
exists (subst e2 x e0).
|
|
constructor.
|
|
assumption.
|
|
|
|
match goal with
|
|
| [ H : exists x, _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (x @ e2).
|
|
constructor.
|
|
assumption.
|
|
|
|
match goal with
|
|
| [ H : exists x, _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (e1 @ x).
|
|
constructor.
|
|
assumption.
|
|
assumption.
|
|
|
|
match goal with
|
|
| [ H : exists x, step e1 _ |- _ ] => invert H
|
|
end.
|
|
right.
|
|
exists (App x e2).
|
|
constructor.
|
|
|
|
assumption.
|
|
Qed.
|
|
|
|
(* Inclusion between typing contexts is preserved by adding the same new mapping
|
|
* to both. *)
|
|
Lemma weakening_override : forall (G G' : fmap var type) x t,
|
|
(forall x' t', G $? x' = Some t' -> G' $? x' = Some t')
|
|
-> (forall x' t', G $+ (x, t) $? x' = Some t'
|
|
-> G' $+ (x, t) $? x' = Some t').
|
|
Proof.
|
|
simplify.
|
|
cases (x ==v x'); simplify; eauto.
|
|
Qed.
|
|
|
|
(* This lemma lets us transplant a typing derivation into a new context that
|
|
* includes the old one. *)
|
|
Lemma weakening : forall G e t,
|
|
has_ty G e t
|
|
-> forall G', (forall x t, G $? x = Some t -> G' $? x = Some t)
|
|
-> has_ty G' e t.
|
|
Proof.
|
|
induct 1; simplify.
|
|
|
|
constructor.
|
|
apply H0.
|
|
assumption.
|
|
|
|
constructor.
|
|
|
|
constructor.
|
|
apply IHhas_ty1.
|
|
assumption.
|
|
apply IHhas_ty2.
|
|
assumption.
|
|
|
|
constructor.
|
|
apply IHhas_ty.
|
|
apply weakening_override.
|
|
assumption.
|
|
|
|
econstructor.
|
|
apply IHhas_ty1.
|
|
assumption.
|
|
apply IHhas_ty2.
|
|
assumption.
|
|
Qed.
|
|
|
|
(* Replacing a variable with a properly typed term preserves typing. *)
|
|
Lemma substitution : forall G x t' e t e',
|
|
has_ty (G $+ (x, t')) e t
|
|
-> has_ty $0 e' t'
|
|
-> has_ty G (subst e' x e) t.
|
|
Proof.
|
|
induct 1; simplify.
|
|
|
|
cases (x0 ==v x).
|
|
|
|
simplify.
|
|
invert H.
|
|
eapply weakening.
|
|
eassumption.
|
|
simplify.
|
|
equality.
|
|
|
|
simplify.
|
|
constructor.
|
|
assumption.
|
|
|
|
constructor.
|
|
|
|
constructor.
|
|
eapply IHhas_ty1; equality.
|
|
eapply IHhas_ty2; equality.
|
|
|
|
cases (x0 ==v x).
|
|
|
|
constructor.
|
|
eapply weakening.
|
|
eassumption.
|
|
simplify.
|
|
cases (x0 ==v x1).
|
|
|
|
simplify.
|
|
assumption.
|
|
|
|
simplify.
|
|
assumption.
|
|
|
|
constructor.
|
|
eapply IHhas_ty.
|
|
maps_equal.
|
|
assumption.
|
|
|
|
econstructor.
|
|
eapply IHhas_ty1; equality.
|
|
eapply IHhas_ty2; equality.
|
|
Qed.
|
|
|
|
(* OK, now we're almost done. Full steps really do preserve typing! *)
|
|
Lemma preservation : forall e1 e2,
|
|
step e1 e2
|
|
-> forall t, has_ty $0 e1 t
|
|
-> has_ty $0 e2 t.
|
|
Proof.
|
|
induct 1; simplify.
|
|
|
|
invert H0.
|
|
invert H4.
|
|
eapply substitution.
|
|
eassumption.
|
|
assumption.
|
|
|
|
invert H.
|
|
constructor.
|
|
|
|
invert H0.
|
|
econstructor.
|
|
apply IHstep.
|
|
eassumption.
|
|
assumption.
|
|
|
|
invert H1.
|
|
econstructor.
|
|
eassumption.
|
|
apply IHstep.
|
|
assumption.
|
|
|
|
invert H0.
|
|
constructor.
|
|
apply IHstep.
|
|
assumption.
|
|
assumption.
|
|
|
|
invert H1.
|
|
constructor.
|
|
assumption.
|
|
apply IHstep.
|
|
assumption.
|
|
Qed.
|
|
|
|
(* Now watch this! Though this syntactic approach to type soundness is usually
|
|
* presented from scratch as a proof technique, it turns out that the two key
|
|
* properties, progress and preservation, are just instances of the same methods
|
|
* we've been applying all along with invariants of transition systems! *)
|
|
Theorem safety : forall e t, has_ty $0 e t
|
|
-> invariantFor (trsys_of e) unstuck.
|
|
Proof.
|
|
simplify.
|
|
|
|
(* Step 1: strengthen the invariant. In particular, the typing relation is
|
|
* exactly the right stronger invariant! Our progress theorem proves the
|
|
* required invariant inclusion. *)
|
|
apply invariant_weaken with (invariant1 := fun e' => has_ty $0 e' t).
|
|
|
|
(* Step 2: apply invariant induction, whose induction step turns out to match
|
|
* our preservation theorem exactly! *)
|
|
apply invariant_induction; simplify.
|
|
equality.
|
|
|
|
eapply preservation.
|
|
eassumption.
|
|
assumption.
|
|
|
|
simplify.
|
|
eapply progress.
|
|
eassumption.
|
|
Qed.
|
|
|
|
|
|
(** * Let's do that again with more automation, whose details are beyond the
|
|
* scope of the book. *)
|
|
|
|
Ltac t0 := match goal with
|
|
| [ H : ex _ |- _ ] => invert H
|
|
| [ H : _ /\ _ |- _ ] => invert H
|
|
| [ |- context[?x ==v ?y] ] => cases (x ==v y)
|
|
| [ H : Some _ = Some _ |- _ ] => invert H
|
|
|
|
| [ H : step _ _ |- _ ] => invert1 H
|
|
| [ H : has_ty _ ?e _, H' : value ?e |- _ ] => invert H'; invert H
|
|
| [ H : has_ty _ _ _ |- _ ] => invert1 H
|
|
end; subst.
|
|
|
|
Ltac t := simplify; propositional; repeat (t0; simplify); try equality; eauto 6.
|
|
|
|
Lemma progress_snazzy : forall e t,
|
|
has_ty $0 e t
|
|
-> value e
|
|
\/ (exists e' : exp, step e e').
|
|
Proof.
|
|
induct 1; t.
|
|
Qed.
|
|
|
|
Local Hint Resolve weakening_override : core.
|
|
|
|
Lemma weakening_snazzy : forall G e t,
|
|
has_ty G e t
|
|
-> forall G', (forall x t, G $? x = Some t -> G' $? x = Some t)
|
|
-> has_ty G' e t.
|
|
Proof.
|
|
induct 1; t.
|
|
Qed.
|
|
|
|
Local Hint Resolve weakening_snazzy : core.
|
|
|
|
(* Replacing a typing context with an equal one has no effect (useful to guide
|
|
* proof search as a hint). *)
|
|
Lemma has_ty_change : forall G e t,
|
|
has_ty G e t
|
|
-> forall G', G' = G
|
|
-> has_ty G' e t.
|
|
Proof.
|
|
t.
|
|
Qed.
|
|
|
|
Local Hint Resolve has_ty_change : core.
|
|
|
|
Lemma substitution_snazzy : forall G x t' e t e',
|
|
has_ty (G $+ (x, t')) e t
|
|
-> has_ty $0 e' t'
|
|
-> has_ty G (subst e' x e) t.
|
|
Proof.
|
|
induct 1; t.
|
|
Qed.
|
|
|
|
Local Hint Resolve substitution_snazzy : core.
|
|
|
|
Lemma preservation_snazzy : forall e1 e2,
|
|
step e1 e2
|
|
-> forall t, has_ty $0 e1 t
|
|
-> has_ty $0 e2 t.
|
|
Proof.
|
|
induct 1; t.
|
|
Qed.
|
|
|
|
Local Hint Resolve progress_snazzy preservation_snazzy : core.
|
|
|
|
Theorem safety_snazzy : forall e t, has_ty $0 e t
|
|
-> invariantFor (trsys_of e)
|
|
(fun e' => value e'
|
|
\/ exists e'', step e' e'').
|
|
Proof.
|
|
simplify.
|
|
apply invariant_weaken with (invariant1 := fun e' => has_ty $0 e' t); eauto.
|
|
apply invariant_induction; simplify; eauto; equality.
|
|
Qed.
|
|
End Stlc.
|