easyctf-2017/paillier-service/description.md
Jacob Magnuson 7f7a8c5e74 typo
2017-03-14 05:17:07 +00:00

252 B

My friend made some sort of encryption service using the Paillier cryptosystem. Can you get him to encrypt the string easyctf{3ncrypt_m3!} for me? Your flag will be a base 10 integer.

Access his encryption service at paillier.tcp.easyctf.com 8570