easyctf-2017/paillier-service/description.md
Jacob Magnuson 7f7a8c5e74 typo
2017-03-14 05:17:07 +00:00

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My friend made some sort of encryption service using the Paillier cryptosystem. Can you get him to encrypt the string `easyctf{3ncrypt_m3!}` for me? Your flag will be a base 10 integer.
Access his encryption service at `paillier.tcp.easyctf.com 8570`