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Jeremy Siek 2020-04-01 09:30:52 -04:00
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@ -515,13 +515,13 @@ Church numerals are more general than natural numbers in that they
represent paths. A path consists of `n` edges and `n + 1` vertices.
We store the vertices in a vector of length `n + 1` in reverse
order. The edges in the path map the ith vertex to the `i + 1` vertex.
The following function `Dˢᵘᶜ` (for denotation of successor) constructs
The following function `D^suc` (for denotation of successor) constructs
a table whose entries are all the edges in the path.
```
Dˢᵘᶜ : (n : ) → Vec Value (suc n) → Value
Dˢᵘᶜ zero (a[0] ∷ []) = ⊥
Dˢᵘᶜ (suc i) (a[i+1] ∷ a[i] ∷ ls) = a[i] ↦ a[i+1] ⊔ Dˢᵘᶜ i (a[i] ∷ ls)
D^suc : (n : ) → Vec Value (suc n) → Value
D^suc zero (a[0] ∷ []) = ⊥
D^suc (suc i) (a[i+1] ∷ a[i] ∷ ls) = a[i] ↦ a[i+1] ⊔ D^suc i (a[i] ∷ ls)
```
We use the following auxilliary function to obtain the last element of
@ -541,7 +541,7 @@ for a given path.
Dᶜ : (n : ) → Vec Value (suc n) → Value
Dᶜ zero (a[0] ∷ []) = ⊥ ↦ a[0] ↦ a[0]
Dᶜ (suc n) (a[n+1] ∷ a[n] ∷ ls) =
(Dˢᵘᶜ (suc n) (a[n+1] ∷ a[n] ∷ ls)) ↦ (vec-last (a[n] ∷ ls)) ↦ a[n+1]
(D^suc (suc n) (a[n+1] ∷ a[n] ∷ ls)) ↦ (vec-last (a[n] ∷ ls)) ↦ a[n+1]
```
* The Church numeral for 0 ignores its first argument and returns
@ -551,11 +551,11 @@ Dᶜ (suc n) (a[n+1] ∷ a[n] ∷ ls) =
⊥ ↦ a[0] ↦ a[0]
* The Church numeral for `suc n` takes two arguments:
a successor function whose denotation is given by `Dˢᵘᶜ`,
a successor function whose denotation is given by `D^suc`,
and the start of the path (last of the vector).
It returns the `n + 1` vertex in the path.
(Dˢᵘᶜ (suc n) (a[n+1] ∷ a[n] ∷ ls)) ↦ (vec-last (a[n] ∷ ls)) ↦ a[n+1]
(D^suc (suc n) (a[n+1] ∷ a[n] ∷ ls)) ↦ (vec-last (a[n] ∷ ls)) ↦ a[n+1]
The exercise is to prove that for any path `ls`, the meaning of the
Church numeral `n` is `Dᶜ n ls`.