test(tests/lean/run): add new test
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2 changed files with 30 additions and 7 deletions
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@ -35,11 +35,4 @@ set_option blast.ematch true
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theorem inv_mul_cancel_left (a b : A) : a⁻¹ * (a * b) = b :=
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theorem inv_mul_cancel_left (a b : A) : a⁻¹ * (a * b) = b :=
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by blast
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by blast
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attribute mul_one [forward]
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attribute inv_mul_cancel_right [forward]
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-- TODO(Leo): check if qfc can get this one
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-- theorem inv_eq_of_mul_eq_one {a b : A} (H : a * b = 1) : a⁻¹ = b :=
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-- by blast
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end
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end
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30
tests/lean/run/blast_ematch6.lean
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30
tests/lean/run/blast_ematch6.lean
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@ -0,0 +1,30 @@
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import algebra.ring data.nat
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open algebra
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variables {A : Type}
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section
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variable [s : group A]
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include s
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set_option blast.simp false
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set_option blast.subst false
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set_option blast.ematch true
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attribute mul_one [forward]
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attribute mul.assoc [forward]
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attribute mul.left_inv [forward]
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attribute one_mul [forward]
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theorem inv_eq_of_mul_eq_one {a b : A} (H : a * b = 1) : a⁻¹ = b :=
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-- This is the kind of theorem that can be easily proved using superposition,
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-- but cannot to be proved using E-matching.
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-- To prove it using E-matching, we must provide the following auxiliary assertion.
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-- E-matching can prove it automatically, and then it is trivial to prove the conclusion
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-- using it.
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-- Remark: this theorem can also be proved using model-based quantifier instantiation (MBQI) available in Z3.
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-- So, we may be able to prove it using qcf.
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assert a⁻¹ * 1 = b, by blast,
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by blast
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end
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