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lean2/tests/lean/elab1.lean.expected.out
Leonardo de Moura f43db96e1f fix(frontends/lean/pp): pretty printer for Type 
Add parenthesis around Type when it has a universe.

Signed-off-by: Leonardo de Moura <leonardo@microsoft.com>
2013-12-19 15:24:45 -08:00

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Set: pp::colors
Set: pp::unicode
Assumed: f
Failed to solve
⊢ (?M::1 ≈ λ x : ℕ, x) ⊕ (?M::1 ≈ nat_to_int) ⊕ (?M::1 ≈ nat_to_real)
(line: 4: pos: 8) Coercion for
10
Failed to solve
⊢ Bool ≺ ℕ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℕ ≺ ?M::0
Substitution
⊢ ?M::5[inst:0 (10)] ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
x : ℕ ⊢ ℕ ≈ ?M::5
Destruct/Decompose
⊢ ℕ → ℕ ≈ Π x : ?M::4, ?M::5
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℕ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ λ x : ℕ, x
Assumption 0
Failed to solve
⊢ Bool ≺ ℤ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℤ ≺ ?M::0
Substitution
⊢ ?M::5[inst:0 (10)] ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
a : ℕ ⊢ ℤ ≈ ?M::5
Destruct/Decompose
⊢ ℕ → ℤ ≈ Π x : ?M::4, ?M::5
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℤ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ nat_to_int
Assumption 1
Failed to solve
⊢ Bool ≺ ℝ
Substitution
⊢ Bool ≺ ?M::0
(line: 4: pos: 6) Type of argument 3 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
⊢ ℝ ≺ ?M::0
Substitution
⊢ ?M::5[inst:0 (10)] ≺ ?M::0
(line: 4: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
?M::1 10
⊤
Assignment
a : ℕ ⊢ ℝ ≈ ?M::5
Destruct/Decompose
⊢ ℕ → ℝ ≈ Π x : ?M::4, ?M::5
Substitution
⊢ ?M::3 ≈ Π x : ?M::4, ?M::5
Function expected at
?M::1 10
Assignment
⊢ ℕ → ℝ ≺ ?M::3
Propagate type, ?M::1 : ?M::3
Assignment
⊢ ?M::1 ≈ nat_to_real
Assumption 2
Assumed: g
Error (line: 7, pos: 8) unexpected metavariable occurrence
Assumed: h
Failed to solve
x : ?M::0, A : Type ⊢ ?M::0 ≺ A
(line: 11: pos: 27) Type of argument 2 must be convertible to the expected type in the application of
h
with arguments:
A
x
Assumed: my_eq
Failed to solve
A : Type, B : Type, a : ?M::0, b : ?M::1, C : Type ⊢ ?M::0[lift:0:3] ≺ C
(line: 15: pos: 51) Type of argument 2 must be convertible to the expected type in the application of
my_eq
with arguments:
C
a
b
Assumed: a
Assumed: b
Assumed: H
Failed to solve
⊢ if ?M::0 (if (if ?M::3 (if a ⊥ ⊤) ⊤) ⊥ ⊤) ⊤ ≺ b
Normalize
⊢ if ?M::0 (?M::3 ∧ a) ⊤ ≺ b
Substitution
⊢ if ?M::0 ?M::1 ⊤ ≺ b
Normalize
⊢ ?M::0 ⇒ ?M::1 ≺ b
(line: 20: pos: 18) Type of definition 't1' must be convertible to expected type.
Assignment
H1 : ?M::2 ⊢ ?M::3 ∧ a ≺ ?M::1
Substitution
H1 : ?M::2 ⊢ ?M::3 ∧ ?M::4 ≺ ?M::1
Destruct/Decompose
⊢ Π H1 : ?M::2, ?M::3 ∧ ?M::4 ≺ Π a : ?M::0, ?M::1
(line: 20: pos: 18) Type of argument 3 must be convertible to the expected type in the application of
Discharge::explicit
with arguments:
?M::0
?M::1
λ H1 : ?M::2, Conj H1 (Conjunct1 H)
Assignment
H1 : ?M::2 ⊢ a ≺ ?M::4
Substitution
H1 : ?M::2 ⊢ ?M::5 ≺ ?M::4
(line: 20: pos: 37) Type of argument 4 must be convertible to the expected type in the application of
Conj::explicit
with arguments:
?M::3
?M::4
H1
Conjunct1 H
Assignment
H1 : ?M::2 ⊢ a ≈ ?M::5
Destruct/Decompose
H1 : ?M::2 ⊢ a ∧ b ≺ ?M::5 ∧ ?M::6
(line: 20: pos: 45) Type of argument 3 must be convertible to the expected type in the application of
Conjunct1::explicit
with arguments:
?M::5
?M::6
H
Failed to solve
⊢ b ≈ a
Substitution
⊢ b ≈ ?M::3
Destruct/Decompose
⊢ b == b ≺ ?M::3 == ?M::4
(line: 22: pos: 22) Type of argument 6 must be convertible to the expected type in the application of
Trans::explicit
with arguments:
?M::1
?M::2
?M::3
?M::4
Refl a
Refl b
Assignment
⊢ a ≈ ?M::3
Destruct/Decompose
⊢ a == a ≺ ?M::2 == ?M::3
(line: 22: pos: 22) Type of argument 5 must be convertible to the expected type in the application of
Trans::explicit
with arguments:
?M::1
?M::2
?M::3
?M::4
Refl a
Refl b
Failed to solve
⊢ (?M::1 ≈ Type) ⊕ (?M::1 ≈ Bool)
Destruct/Decompose
⊢ ?M::1 ≺ Type
(line: 24: pos: 6) Type of argument 1 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Failed to solve
⊢
(?M::0 ≈ Type) ⊕ (?M::0 ≈ (Type 1)) ⊕ (?M::0 ≈ (Type 2)) ⊕ (?M::0 ≈ (Type M)) ⊕ (?M::0 ≈ (Type U))
Destruct/Decompose
⊢ Type ≺ ?M::0
(line: 24: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Failed to solve
⊢ (Type 1) ≺ Type
Substitution
⊢ (Type 1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type
Assumption 1
Assignment
⊢ ?M::1 ≈ Type
Assumption 0
Failed to solve
⊢ (Type 2) ≺ Type
Substitution
⊢ (Type 2) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type 1)
Assumption 2
Assignment
⊢ ?M::1 ≈ Type
Assumption 0
Failed to solve
⊢ (Type 3) ≺ Type
Substitution
⊢ (Type 3) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type 2)
Assumption 3
Assignment
⊢ ?M::1 ≈ Type
Assumption 0
Failed to solve
⊢ (Type M+1) ≺ Type
Substitution
⊢ (Type M+1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type M)
Assumption 4
Assignment
⊢ ?M::1 ≈ Type
Assumption 0
Failed to solve
⊢ (Type U+1) ≺ Type
Substitution
⊢ (Type U+1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type U)
Assumption 5
Assignment
⊢ ?M::1 ≈ Type
Assumption 0
Failed to solve
⊢
(?M::0 ≈ Type) ⊕ (?M::0 ≈ (Type 1)) ⊕ (?M::0 ≈ (Type 2)) ⊕ (?M::0 ≈ (Type M)) ⊕ (?M::0 ≈ (Type U))
Destruct/Decompose
⊢ Type ≺ ?M::0
(line: 24: pos: 6) Type of argument 2 must be convertible to the expected type in the application of
f::explicit
with arguments:
?M::0
Bool
Bool
Failed to solve
⊢ (Type 1) ≺ Bool
Substitution
⊢ (Type 1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ Type
Assumption 7
Assignment
⊢ ?M::1 ≈ Bool
Assumption 6
Failed to solve
⊢ (Type 2) ≺ Bool
Substitution
⊢ (Type 2) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type 1)
Assumption 8
Assignment
⊢ ?M::1 ≈ Bool
Assumption 6
Failed to solve
⊢ (Type 3) ≺ Bool
Substitution
⊢ (Type 3) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type 2)
Assumption 9
Assignment
⊢ ?M::1 ≈ Bool
Assumption 6
Failed to solve
⊢ (Type M+1) ≺ Bool
Substitution
⊢ (Type M+1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type M)
Assumption 10
Assignment
⊢ ?M::1 ≈ Bool
Assumption 6
Failed to solve
⊢ (Type U+1) ≺ Bool
Substitution
⊢ (Type U+1) ≺ ?M::1
Propagate type, ?M::0 : ?M::1
Assignment
⊢ ?M::0 ≈ (Type U)
Assumption 11
Assignment
⊢ ?M::1 ≈ Bool
Assumption 6
Failed to solve
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ if (if a b ⊤) a ⊤ ≺ a
Normalize
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ (a ⇒ b) ⇒ a ≺ a
Substitution
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ (a ⇒ b) ⇒ a ≺ ?M::5[lift:0:1]
Substitution
a : Bool, b : Bool, H : ?M::2, H_a : ?M::6 ⊢ ?M::2[lift:0:2] ≺ ?M::5[lift:0:1]
Destruct/Decompose
a : Bool, b : Bool, H : ?M::2 ⊢ Π H_a : ?M::6, ?M::2[lift:0:2] ≺ Π a : ?M::3, ?M::5[lift:0:1]
(line: 27: pos: 21) Type of argument 5 must be convertible to the expected type in the application of
DisjCases::explicit
with arguments:
?M::3
?M::4
?M::5
EM a
λ H_a : ?M::6, H
λ H_na : ?M::7, NotImp1 (MT H H_na)
Normalize assignment
?M::0
Assignment
a : Bool, b : Bool ⊢ ?M::2 ≈ ?M::0
Destruct/Decompose
a : Bool, b : Bool ⊢ Π H : ?M::2, ?M::5 ≺ Π a : ?M::0, ?M::1[lift:0:1]
(line: 27: pos: 4) Type of argument 3 must be convertible to the expected type in the application of
Discharge::explicit
with arguments:
?M::0
?M::1
λ H : ?M::2,
DisjCases (EM a) (λ H_a : ?M::6, H) (λ H_na : ?M::7, NotImp1 (MT H H_na))
Assignment
a : Bool, b : Bool ⊢ ?M::0 ≈ (a ⇒ b) ⇒ a
Destruct/Decompose
a : Bool, b : Bool ⊢ ?M::0 ⇒ ?M::1 ≺ ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
a : Bool ⊢ Π b : Bool, ?M::0 ⇒ ?M::1 ≺ Π b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
⊢ Π a b : Bool, ?M::0 ⇒ ?M::1 ≺ Π a b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
(line: 26: pos: 16) Type of definition 'pierce' must be convertible to expected type.
Assignment
a : Bool, b : Bool, H : ?M::2 ⊢ ?M::5 ≺ a
Substitution
a : Bool, b : Bool, H : ?M::2 ⊢ ?M::5 ≺ ?M::1[lift:0:1]
Destruct/Decompose
a : Bool, b : Bool ⊢ Π H : ?M::2, ?M::5 ≺ Π a : ?M::0, ?M::1[lift:0:1]
(line: 27: pos: 4) Type of argument 3 must be convertible to the expected type in the application of
Discharge::explicit
with arguments:
?M::0
?M::1
λ H : ?M::2, DisjCases (EM a) (λ H_a : ?M::6, H) (λ H_na : ?M::7, NotImp1 (MT H H_na))
Assignment
a : Bool, b : Bool ⊢ ?M::1 ≈ a
Destruct/Decompose
a : Bool, b : Bool ⊢ ?M::0 ⇒ ?M::1 ≺ ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
a : Bool ⊢ Π b : Bool, ?M::0 ⇒ ?M::1 ≺ Π b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
Destruct/Decompose
⊢ Π a b : Bool, ?M::0 ⇒ ?M::1 ≺ Π a b : Bool, ((a ⇒ b) ⇒ a) ⇒ a
(line: 26: pos: 16) Type of definition 'pierce' must be convertible to expected type.
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