update
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6 changed files with 280 additions and 13 deletions
3
.gitignore
vendored
3
.gitignore
vendored
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.direnv
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.*.aux
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*.pdf
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*.pdf
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*.agdai
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27
Exercises1.agda
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27
Exercises1.agda
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module Exercises1 where
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open import Agda.Primitive
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open import foundation-core.empty-types
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open import foundation-core.equivalences
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open import foundation-core.negation
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open import foundation.dependent-pair-types
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open import foundation.identity-types
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open import foundation.univalence
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open import foundation.sections
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open import foundation.retractions
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_≡_ = _=_
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⊥ = empty
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equal-to-zero : {A : Set} (f : ¬ A) → A ≡ ⊥
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equal-to-zero {A} f = eq-equiv A ⊥ eqv
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where
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s : section f
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s = (λ ()) , λ x → ex-falso x
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r : retraction f
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r = (λ ()) , λ x → ex-falso (f x)
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eqv : A ≃ ⊥
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eqv = f , s , r
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56
Exercises1.v
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56
Exercises1.v
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Require Import UniMath.Foundations.All.
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Inductive empty : Type := .
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Definition slide16_exercise (t : empty): bool :=
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match t with end.
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Definition slide18_exercise (t : nat): bool :=
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match t with
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| O => true
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| S _ => false
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end.
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(* Slide 22, Exercise 1*)
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Definition fst {A B : Type} (p : A × B): A.
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Proof.
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induction p.
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apply pr1.
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Defined.
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(* Show Proof. *)
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Definition snd {A B : Type} (p : A × B): B.
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Proof.
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induction p.
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apply pr2.
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Defined.
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Definition swap {A B : Type} (p : A × B): B × A :=
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match p with (a ,, b) => (b ,, a) end.
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(* Definition swap {A B : Type} (p : A × B): B × A.
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Proof.
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induction p.
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constructor.
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- apply pr2.
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- apply pr1.
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Defined. *)
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(* Slide 38, Exercise: transport *)
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Definition transport {A : Type} {B : A -> Type}
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{x y : A} (p : paths x y) (bx : B x): B y.
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induction p.
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apply bx.
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Defined.
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(* Show Proof. *)
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(* Slide 39, Exercise: swap involutive *)
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Definition slide39_exercise {A B : Type} (t : A × B) : paths (swap (swap t)) t.
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reflexivity.
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Show Proof.
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(* Slide 44, Exercise: neg *)
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(* Definition slide44_exercise {A : Type} : not *)
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198
Lecture1.typ
198
Lecture1.typ
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@ -11,6 +11,10 @@ Important features in MLTT:
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#let Nat = $sans("Nat")$
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#let Vect = $sans("Vect")$
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#let Bool = $sans("Bool")$
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#let tru = $sans("true")$
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#let fls = $sans("false")$
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- Dependent types and functions.
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e.g $ "concatenate": Pi_(m,n:"Nat") Vect(m) -> Vect(n) -> Vect(m+n) $
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- Function arrows always associate to the right.
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@ -36,11 +40,13 @@ $ "context" tack.r "conclusion" $
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Example:
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$ "isZero?"& : Nat -> "Bool" \
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"isZero?"& (n) :defeq "??"
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#let isZero = $sans("isZero?")$
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$ isZero& : Nat -> Bool \
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isZero& (n) :defeq "??"
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$
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At this point, looking for $(n: Nat) tack.r "isZero?"(n) : "Bool"$.
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At this point, looking for $(n: Nat) tack.r isZero(n) : Bool$.
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=== Inference rules
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@ -96,13 +102,16 @@ If $a defeq a'$ then $f @ a defeq f @ a'$.
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Example (context $Gamma$ are elided):
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=== Functions
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#typeIntroTable(
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[If $A$ and $B$ are types, then $A -> B$ is a type
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#prooftree(axiom($Gamma tack.r A$), axiom($Gamma tack.r B$), rule(n: 2, $Gamma tack.r A -> B$))],
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[If $(x : A) tack.r b : B$, then $tack.r lambda (x : A) . b(x) : A -> B$
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- $b$ is an expression that might involve $x$],
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[If we have a function $f : A -> B$, and $a : A$, then $f @ a : B$ (or $f(a) : B$)],
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[What is the result of the application? $(lambda(x : A) . b(x)) @ a defeq subst(a, x, b)$
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[What is the result of the application? \
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$(lambda(x : A) . b(x)) @ a defeq subst(a, x, b)$
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- Substitution $subst(a, x, b)$ is built-in],
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)
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@ -112,9 +121,12 @@ Questions:
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Another example: the singleton type
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=== Unit type
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#let unit = $bb(1)$
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#let tt = $t t$
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#let tt = $star$
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#let rec = $sans("rec")$
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#let ind = $sans("ind")$
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#typeIntroTable(
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[$unit$ is a type],
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@ -127,11 +139,7 @@ Another example: the singleton type
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- Question: *How to construct this using lambda abstraction?*
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- (Structural rule: having $tack.r c : C$ means $x : unit tack.r c : C$, which by the lambda introduction rule gives us $lambda x.c : unit -> C$)
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Booleans
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#let Bool = $sans("Bool")$
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#let tru = $sans("true")$
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#let fls = $sans("false")$
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=== Booleans
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#typeIntroTable(
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[$Bool$ is a type],
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[$rec_Bool (C, c, c', tru) defeq c$ and $rec_Bool (C, c, c', fls) defeq c'$],
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)
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Empty type
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=== Empty type
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#let empty = $bb(0)$
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@ -151,7 +159,7 @@ Empty type
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[_(no computation rule)_],
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)
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Natural numbers
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=== Natural numbers
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#let zero = $sans("zero")$
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#let suc = $sans("suc")$
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@ -166,3 +174,169 @@ Natural numbers
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We can define computation rule on naturals using a universal property],
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)
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=== Pattern matching
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*Exercise.* Define a function $isZero : Nat -> Bool$.
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*Solution.* $isZero :defeq lambda (x : Nat) . rec_Nat (Bool , tru, lambda (x : Bool) . fls , x)$.
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This is cumbersome and prone to mistakes. Instead we use pattern matching. A function $A -> C$ is completely specified if it's specified on the *canonical elements* of $A$.
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$ isZero& : Nat -> Bool \
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isZero& zero defeq tru \
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isZero& suc (n) defeq fls \
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$
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=== Pairs
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#let pair = $sans("pair")$
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#typeIntroTable(
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[If $A$ and $B$ are types, then $A times B$ is a type],
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[If $a : A$ and $b : B$, then $pair(a, b) : A times B$],
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[If $C$ is a type, and $p : A -> B -> C$ and $t : A times B$, then $rec_times (A, B, C, p, t) : C$],
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[...],
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)
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#let fst = $sans("fst")$
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#let snd = $sans("snd")$
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#let swap = $sans("swap")$
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#let assoc = $sans("assoc")$
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*Exercise.* Define $snd : A times B -> A$ and $snd : A times B -> B$.
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*Exercise.* Given types $A$ and $B$, write a function $swap$ of type $A times B -> B times A$.
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*Exercise.* What is the type of $swap @ pair (tt , fls)$?
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*Exercise.* Write a function $assoc$ of type $(A times B) times C -> A times (B times C)$
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=== Type dependency
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In particular: dependent type $B$ over $A$. (read "family $B$ of types indexed by $A$")
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Example: type of vectors.
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$ n : Nat tack.r Vect(n) $
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=== Universes
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#let Type = $sans("Type")$
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There is a type $Type$. Its elements are types ($A : Type$). The dependent function $x : A tack.r B$ can be considered a function $lambda x . B : A -> Type$.
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What is the type of $Type$? $Type$ is in an indexed hierarchy to avoid type-in-type paradox. We usually omit the index: $Type_i : Type_(i + 1)$
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=== Dependent functions $product_(x : A) B$
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#typeIntroTable(
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[If $A$ is a type, and $B$ is a type family indexed by $A$, then there is a type $product_(x : A) B$],
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[If $(x : A) tack.r b : B$, then $lambda (x : A) . b : product_(x : A) B$],
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[If $f : product_(x : A) B$ and $a : A$, then $f(a) : subst(x, a, B)$],
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[$(lambda (x : A) . b) ( a) defeq subst(x, a, b)$
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- The case $A -> B$ is a special case of the dependent function, where $B$ doesn't depend on $x : A$],
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)
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=== Dependent pairs $Sigma_(x : A) B$
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#typeIntroTable(
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[If $x : A tack.r B$, then there is a type $Sigma_(x : A) B$],
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[If $a : A$ and $b : B(a)$, then $pair (a, b) : Sigma_(x : A) B$],
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[...],
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[...
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- The case $A times B$ is a special case of the dependent function, where $B$ doesn't depend on $x : A$],
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)
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=== Identity type
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#let Id = $sans("Id")$
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#let refl = $sans("refl")$
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#let propeq = $=$
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#typeIntroTable(
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[If $a : A$ and $b : A$, then $Id_A (a, b)$ is a type],
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[If $a : A$, then $refl(a) : Id_A (a, a)$],
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[
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- If $(x, y : A), (p : Id_A (x, y)) tack.r C (x, y, p)$
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- and $(x : A) tack.r t(x) : C(x, x, refl(x))$
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- then $(x, y : A), (p : Id_A (x, y)) tack.r ind_Id (t; x, y, p) : C(x, y, p)$],
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[...],
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)
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- (There are dependent versions of each of the previous elimination rules that resulted in $C$)
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- $ind$ "induction" is used more when the $C$ is dependent, while $rec$ is better for non-dependent $C$'s.
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For example, to define:
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#let sym = $sans("sym")$
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$ sym : product_(x, y : A) Id(x, y) -> Id(y, x) $
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it suffices to just specify its image on $(x, x, refl)$
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#prooftree(
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axiom($x : A tack.r refl(x) : Id(x, x)$),
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rule($(x, y : A) , (p : Id(x, y)) tack.r Id(y, x)$),
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rule($x, y : A tack.r Id(x, y) -> Id(y, x)$),
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rule($sym : product_(x, y : A) Id(x, y) -> Id(y, x)$)
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)
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So $sym(x, x, refl(x)) :defeq refl(x)$
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#let transport = $sans("transport")$
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*Exercise.* Define $transport^B : product_(x, y : A) Id(x, y) -> B(x) -> B(y)$.
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*Exercise: swap is involutive.* Given types $A$ and $B$, write a function $product_(t : A times B) Id(swap(swap(t)), t)$
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=== Disjoint sum
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#let inl = $sans("inl")$
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#let inr = $sans("inr")$
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#typeIntroTable(
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[If $A$ and $B$ are types, then $A + B$ is a type],
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[
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- If $a : A$, then $inl(a) : A + B$
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- If $b : B$, then $inr(b) : A + B$
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],
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[If $f : A -> C$ and $g : B ->C $ then $rec_+ (C, f, g) : A + B -> C$],
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[
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- $rec_+ (C, f, g)( inl(a)) defeq f(a)$
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- $rec_+ (C, f, g)( inr(b)) defeq g(a)$
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],
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)
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=== Interpreting types as sets and propositions
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#table(
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columns: 3,
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stroke: 0in,
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[$A$], [set $A$], [proposition $A$],
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[$a:A$], [$a in A$], [$a$ is a proof of $A$],
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[$unit$], [], [$top$],
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[$empty$], [], [$bot$],
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[$A times B$], [cartesian product], [$A and B$],
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[$A + B$], [disjoint unions $A B$], [$A or B$],
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[$A -> B$], [set of functions $A -> B$], [$A => B$],
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[$x : A tack.r B(x)$], [], [predicate $B$ on $A$],
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[$sum_(x : A) B(x)$], [], [$exists x in A, B(x)$],
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[$product_(x : A) B(x)$], [], [$forall x in A, B(x)$],
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[$Id_A (a, b)$], [], [equality $a = b$],
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)
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The connectives $forall$ and $exists$ behave constructively.
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The interpretation into propositions is known as the *Curry-Howard correspondence*.
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=== Negation
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$ not A :defeq A -> empty $
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*Exercise.* Construct a term of type $A -> not not A$.
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*Exercise ($tru eq.not fls$).* Construct a term of type $not Id(tru, fls)$.
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*Solution.* Let $B :defeq rec_Bool (Type, unit, empty)$. Then $B(tru) defeq unit$ and $B(fls) defeq empty$. Then:
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$ lambda (p : Id(tru, fls)) . transport^B (p, tt) : Id(tru, fls) -> empty $
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7
Lecture2.typ
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7
Lecture2.typ
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= Coq
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UniMath is library for univalent math.
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Plain coq has general coinductive datatypes and other things we will not use.
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Also, univalence axiom is assumed.
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2
unimath2024.agda-lib
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2
unimath2024.agda-lib
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depend: agda-unimath
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include: .
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