frap/Sets.v

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2015-12-31 20:44:34 +00:00
Require Import Classical FunctionalExtensionality List.
Set Implicit Arguments.
Axiom prop_ext : forall P Q : Prop,
(P <-> Q) -> P = Q.
Section set.
Variable A : Type.
Definition set := A -> Prop.
Definition In (x : A) (s : set) := s x.
Definition constant (ls : list A) : set := fun x => List.In x ls.
Definition universe : set := fun _ => True.
Definition check (P : Prop) : set := fun _ => P.
Definition union (s1 s2 : set) : set := fun x => s1 x \/ s2 x.
Definition intersection (s1 s2 : set) : set := fun x => s1 x /\ s2 x.
Definition complement (s : set) : set := fun x => ~s x.
Definition subseteq (s1 s2 : set) := forall x, s1 x -> s2 x.
Definition subset (s1 s2 : set) := subseteq s1 s2 /\ ~subseteq s2 s1.
Definition scomp (P : A -> Prop) : set := P.
Theorem sets_equal : forall s1 s2 : set, (forall x, s1 x <-> s2 x) -> s1 = s2.
Proof.
intros.
apply functional_extensionality; intros.
apply prop_ext; auto.
Qed.
End set.
Infix "\in" := In (at level 70).
Notation "{ }" := (constant nil).
Notation "{ x1 , .. , xN }" := (constant (cons x1 (.. (cons xN nil) ..))).
Notation "[ P ]" := (check P).
Infix "\cup" := union (at level 40).
Infix "\cap" := intersection (at level 40).
Infix "\subseteq" := subseteq (at level 70).
Infix "\subset" := subset (at level 70).
Notation "[ x | P ]" := (scomp (fun x => P)).
Ltac sets' tac :=
unfold In, constant, universe, check, union, intersection, complement, subseteq, subset, scomp in *;
tauto || intuition tac.
Ltac sets tac :=
try match goal with
| [ |- @eq (set _) _ _ ] => apply sets_equal; intro; split
end; sets' tac.
(** * Some of the usual properties of set operations *)
Section properties.
Variable A : Type.
Variable x : A.
Variables s1 s2 s3 : set A.
Theorem union_comm : s1 \cup s2 = s2 \cup s1.
Proof.
sets idtac.
Qed.
Theorem union_assoc : (s1 \cup s2) \cup s3 = s1 \cup (s2 \cup s3).
Proof.
sets idtac.
Qed.
Theorem intersection_comm : s1 \cap s2 = s2 \cap s1.
Proof.
sets idtac.
Qed.
Theorem intersection_assoc : (s1 \cap s2) \cap s3 = s1 \cap (s2 \cap s3).
Proof.
sets idtac.
Qed.
Theorem not_union : complement (s1 \cup s2) = complement s1 \cap complement s2.
Proof.
sets idtac.
Qed.
Theorem not_intersection : complement (s1 \cap s2) = complement s1 \cup complement s2.
Proof.
sets idtac.
Qed.
Theorem subseteq_refl : s1 \subseteq s1.
Proof.
unfold subseteq; eauto.
Qed.
Theorem subseteq_In : s1 \subseteq s2 -> x \in s1 -> x \in s2.
Proof.
unfold subseteq, In; eauto.
Qed.
Theorem cap_split : forall (P1 P2 : A -> Prop),
(forall s, P1 s \/ P2 s)
-> s1 \cap [s | P1 s] \subseteq s2
-> s1 \cap [s | P2 s] \subseteq s3
-> s1 \subseteq (s2 \cap [s | P1 s]) \cup (s3 \cap [s | P2 s]).
Proof.
intros; sets eauto.
specialize (H x0).
specialize (H0 x0).
specialize (H1 x0).
tauto.
Qed.
Variables ss1 ss2 : list A.
Theorem union_constant : constant ss1 \cup constant ss2 = constant (ss1 ++ ss2).
Proof.
unfold constant, union; simpl.
apply sets_equal; simpl; intuition.
Qed.
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End properties.
Hint Resolve subseteq_refl subseteq_In.
Hint Rewrite union_constant.
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(** * Removing duplicates from constant sets *)
Inductive removeDups A : list A -> list A -> Prop :=
| RdNil : removeDups nil nil
| RdNew : forall x ls ls',
~List.In x ls
-> removeDups ls ls'
-> removeDups (x :: ls) (x :: ls')
| RdDup : forall x ls ls',
List.In x ls
-> removeDups ls ls'
-> removeDups (x :: ls) ls'.
Theorem removeDups_fwd : forall A x (ls ls' : list A),
removeDups ls ls'
-> List.In x ls
-> List.In x ls'.
Proof.
induction 1; simpl; intuition.
subst; eauto.
Qed.
Theorem removeDups_bwd : forall A x (ls ls' : list A),
removeDups ls ls'
-> List.In x ls'
-> List.In x ls.
Proof.
induction 1; simpl; intuition.
Qed.
Theorem removeDups_ok : forall A (ls ls' : list A),
removeDups ls ls'
-> constant ls = constant ls'.
Proof.
intros.
apply sets_equal.
unfold constant; intuition eauto using removeDups_fwd, removeDups_bwd.
Qed.
Ltac removeDups :=
match goal with
| [ |- context[constant ?ls] ] =>
erewrite (@removeDups_ok _ ls)
by repeat (apply RdNil
|| (apply RdNew; [ simpl; intuition congruence | ])
|| (apply RdDup; [ simpl; intuition congruence | ]))
end.