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Typo fix (issue #14)
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@ -2779,7 +2779,7 @@ These rules together are \emph{complete}\index{completeness of Hoare logic}, in
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Here we only go into detail on a proof of the dual property, \emph{soundness}\index{soundness of Hoare logic}.
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\begin{lemma}\label{hoare_while}
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Assume the following fact: Together, $\bigstep{(h, v, c)}{(h', v')}$, $I(h, v)$, and $\denote{b}(h, s)$ imply $I(h', v')$.
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Assume the following fact: Together, $\bigstep{(h, v, c)}{(h', v')}$, $I(h, v)$, and $\denote{b}(h, v)$ imply $I(h', v')$.
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Then, given $\bigstep{(h, v, \{I\} \while{b}{c})}{(h', v')}$, it follows that $I(h', v')$ and $\neg \denote{b}(h', v')$.
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\end{lemma}
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\begin{proof}
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