Michael Zhang
a08f1206c2
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147 lines
3.5 KiB
Markdown
147 lines
3.5 KiB
Markdown
+++
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title = "Proving true ≢ false"
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slug = "proving-true-from-false"
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date = 2023-04-21
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tags = ["type-theory", "agda"]
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math = true
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+++
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<details>
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<summary>Imports</summary>
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These are some imports that are required for code on this page to work properly.
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```agda
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{-# OPTIONS --cubical #-}
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open import Cubical.Foundations.Prelude
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open import Data.Bool
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open import Data.Unit
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open import Data.Empty
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¬_ : Set → Set
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¬ A = A → ⊥
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infix 4 _≢_
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_≢_ : ∀ {A : Set} → A → A → Set
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x ≢ y = ¬ (x ≡ y)
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```
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</details>
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The other day, I was trying to prove `true ≢ false` in Agda. I would write the
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statement like this:
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```
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true≢false : true ≢ false
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```
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For many "obvious" statements, it suffices to just write `refl` since the two
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sides are trivially true via rewriting. For example:
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```
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open import Data.Nat
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1+2≡3 : 1 + 2 ≡ 3
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1+2≡3 = refl
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```
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This is saying that using the way addition is defined, we can just rewrite the
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left side so it becomes judgmentally equal to the right:
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```
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-- For convenience, here's the definition of addition:
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-- _+_ : Nat → Nat → Nat
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-- zero + m = m
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-- suc n + m = suc (n + m)
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```
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- 1 + 2
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- suc zero + suc (suc zero)
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- suc (zero + suc (suc zero))
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- suc (suc (suc zero))
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- 3
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However, in cubical Agda, naively using `refl` with the inverse statement
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doesn't work. I've commented it out so the code on this page can continue to
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compile.
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```
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-- true≢false = refl
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```
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It looks like it's not obvious to the interpreter that this statement is
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actually true. Why is that
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---
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Well, in constructive logic / constructive type theory, proving something is
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false is actually a bit different. You see, the definition of the `not`
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operator, or $\neg$, was:
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```
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-- ¬_ : Set → Set
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-- ¬ A = A → ⊥
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```
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> The code is commented out because it was already defined at the top of the
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> page in order for the code to compile.
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This roughly translates to, "give me any proof of A, and I'll produce a value of
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the bottom type." Since the bottom type $\bot$ is a type without values, being
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able to produce a value represents logical falsehood. So we're looking for a way
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to ensure that any proof of `true ≢ false` must lead to $\bot$.
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The strategy here is we define some kind of "type-map". Every time we see
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`true`, we'll map it to some arbitrary inhabited type, and every time we see
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`false`, we'll map it to empty.
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```
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bool-map : Bool → Type
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bool-map true = ⊤
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bool-map false = ⊥
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```
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This way, we can use the fact that transporting
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over a path (the path supposedly given to us as the witness that true ≢ false)
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will produce a function from the inhabited type we chose to the empty type!
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```
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true≢false p = transport (λ i → bool-map (p i)) tt
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```
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I used `true` here, but I could equally have just used anything else:
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```
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bool-map2 : Bool → Type
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bool-map2 true = 1 ≡ 1
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bool-map2 false = ⊥
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true≢false2 : true ≢ false
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true≢false2 p = transport (λ i → bool-map2 (p i)) refl
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```
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---
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Let's make sure this isn't broken by trying to apply this to something that's
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actually true:
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```
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2-map : ℕ → Type
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2-map 2 = ⊤
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2-map 2 = ⊥
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2-map else = ⊤
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-- 2≢2 : 2 ≢ 2
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-- 2≢2 p = transport (λ i → 2-map (p i)) tt
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```
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I commented the lines out because they don't compile, but if you tried to
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compile it, it would fail with:
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```text
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⊤ !=< ⊥
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when checking that the expression transport (λ i → 2-map (p i)) tt
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has type ⊥
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```
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That's because with identical terms, you can't simultaneously assign them to
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different values, or else it would not be a proper function.
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